Answer: Answer:
Plane B was farthest away from the airport
Step-by-step explanation:
"This question requires you to visualize the run way as the horizontal distance to be covered, the height from the ground as the height gained by the plane after take of and the distance from the airport as the displacement due to the angle of take off.
In plane A
The take-off angle is 44° and the height gained is 22 ft.
Apply the relationship for sine of an angle;
Sine Ф°= opposite side length÷hypotenuse side length
The opposite side length is the height gained by plane which is 22 ft
The angle is 44° and the distance the plane will be away from the airport after take-off will be represented by the value of hypotenuse
Applying the formula
sin Ф=O/H where O=length of the side opposite to angle 44° and H is the hypotenuse
In plane B
Angle of take-off =40°, height of plane=22miles finding the hypotenuse
Solution
After take-off and reaching a height of 22 ft from the ground, plane A will be 31.67 miles from the airport
After take-off and reaching a height of 22 ft from the ground, plane B will be 34.23 miles away from the airport."
Excerpt from Brainly
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