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lys-0071 [83]
3 years ago
7

A model predicts the profit, p of a company as p(x) = x3 – 3x2 – 16x + 48, where p is in thousands of dollars and x is number of

years passed since January 1, 2011. For which time interval would the company make a loss?
Mathematics
1 answer:
zavuch27 [327]3 years ago
3 0
The first step is to determine the zeros of p(x).
From the Remainder Theorem, 
p(a) = 0  => (x-a) is a factor of p(x), and x=a is a zero of p(x).

Try x=3:
p(3) = 3^3 - 3*3^2 - 16*3 + 48 = 27 - 27 - 48 + 48 = 0
Therefore x=3 is a zero, and (x-3) is a factor of p(x).

Perform long division.
                    x²             -  16
      -------------------------------------
x-3 |  x³  -  3x²  -  16x  +  48
         x³  -  3x²
        -----------------------------------
                         -  16x  + 48
                         -  16x  +  48         

Note that x² - 6 = (x+4)(x-4).

Therefore the complete factorization of p(x) is
p(x) = (x-3)(x+4)(x-4)

To determine when p(x) is negative, we shall test between the zeros of p(x)
   x      p(x)       Sign
----  ---------    ---------
  -4          0    
   0        48         +
   3           0
3.5   -1.875         -
   4           0

p(x) is negative in the interval x = (3, 4).

Answer
The time interval is Jan. 1, 2014 to Jan. 1, 2015.
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An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden
Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

p_1=X_1/n_1=180/500=0.36

The sample 2, of size n2=600 has a proportion of p2=0.25.

p_1=X_1/n_1=150/600=0.25.

The difference between proportions is (p1-p2)=0.11.

p_d=p_1-p_2=0.36-0.25=0.11

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=2\cdot P(t>3.964)=0.000078

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544

Then, the lower and upper bounds of the confidence interval are:

LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439

The  95% confidence interval for the population mean is (0.0556, 0.1644).

5 0
3 years ago
Evaluate the expression for<br> X= 5, y = 1:<br> X + 15<br> y + 1
lapo4ka [179]

Answer:

20

2

Step-by-step explanation:

lets substitute the value of x and y in the equations:

5 + 15 =20

1 + 1 =2

7 0
3 years ago
What is the formula for the following arithmetic sequence?
vlabodo [156]

a_{n} = 12 + (- 6)(n - 1 )

This is an arithmetic sequence with n th term

a_{n} = a_{1} + (n - 1)d

here d = - 6 - 0 = 0 - 6 = 6 - 12 = -6 and a_{1} = 12, hence

a_{n} = 12 + (- 6)(n - 1)

use this formula to find the 30 th term

a_{30} = 12 + (- 6 × 29) = 12 - 174 = - 162



4 0
3 years ago
What is the answer to 3a^-2/a^-3
steposvetlana [31]

Answer:

3a

Step-by-step explanation:

6 0
2 years ago
What is the value of x?
nikklg [1K]
It took me a minute, but I understand what it wants you to do.

a^2+b^2=c^2

Find the missing length on that one triangle to the left.

62^2+b^2= 99.2^2

Square the numbers. 

3844+b^2= 9840.64

Subtract 3844 on both sides. 

b^2= 5996.64 

Square root it. 

b= 77. 437975 round down to b= 77.4 

Now, we can find the length of the other missing side. (x+2)

77.4^2+b^2= 112^2

5990.76+b^2= 12,544

Subtract 5990.76 on both sides. 

b^2= 6553.24

Square root it. 

b= 80.952085, round to b=81

Now, plug that in. 

(x+2)= 81

Subtract 2 on both sides. 

x=79 (about)

I hope this helps! Make sure to check my work. 
~kaikers





4 0
3 years ago
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