A model predicts the profit, p of a company as p(x) = x3 – 3x2 – 16x + 48, where p is in thousands of dollars and x is number of years passed since January 1, 2011. For which time interval would the company make a loss?
1 answer:
The first step is to determine the zeros of p(x). From the Remainder Theorem, p(a) = 0 => (x-a) is a factor of p(x), and x=a is a zero of p(x). Try x=3: p(3) = 3^3 - 3*3^2 - 16*3 + 48 = 27 - 27 - 48 + 48 = 0 Therefore x=3 is a zero, and (x-3) is a factor of p(x). Perform long division. x² - 16 ------------------------------------- x-3 | x³ - 3x² - 16x + 48 x³ - 3x² ----------------------------------- - 16x + 48 - 16x + 48 Note that x² - 6 = (x+4)(x-4). Therefore the complete factorization of p(x) is p(x) = (x-3)(x+4)(x-4) To determine when p(x) is negative, we shall test between the zeros of p(x) x p(x) Sign ---- --------- --------- -4 0 0 48 + 3 0 3.5 -1.875 - 4 0 p(x) is negative in the interval x = (3, 4). Answer The time interval is Jan. 1, 2014 to Jan. 1, 2015.
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