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Arturiano [62]
3 years ago
13

What is the value of c?

Mathematics
1 answer:
Ymorist [56]3 years ago
7 0
34 if you divide then it will lead to a total of 34
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What is the equation?
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Shawna is a member of the swim team. She can swim 3 laps in 3 minutes
likoan [24]

Answer:

8 mins 56 secs

Step-by-step explanation:

3 minutes and 21 seconds divided by 3 laps is 1.07 so it takes her 1 minute and 0.7 sec for each lap then u just multuply 1.07 by 8 and u get 8.56 meaning 8 mins and 56 secs. hope i helped :)

6 0
2 years ago
What is the least common denominator of the rational expressions below?
Lyrx [107]

Answer:

B.(x-6)

Step-by-step explanation:

12/(x^2 - 11x+30) - 43/(x^2-6x)

12/((x - 5) (x - 6)) - 43/x(x-6) [Factoring the denominator]

Both have x-6 common in the denominator,

4 0
2 years ago
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
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