What is the value of c?

Will give brainliest!! Using the measurements of the shapes.. determine the area and perimeter of the irregular polygon.

yan [13]

Answer:

$p=28.2\:\text{units},\\A=40.2\:\text{square units}}$

Step-by-step explanation:

The irregular shape's area consists of the sum of the areas of all the shapes that make it up.

Area of pink triangle: $\frac{1}{2}\cdot 3 \cdot 3=4.5$

Area of purple square: $3^2=9$

Area of green quadrilateral: $3\cdot 2.9=8.7$

Area of blue triangle: $\sqrt{10.25(10.25-8.5)(10.25-6)(10.25-6)}=17.99989$

Therefore, the area of the irregular polygon is $4.5+9+8.7+17.99989\approx \boxed{40.2\:\text{square units}}$ .

The perimeter of the irregular polygon consists of certain shred sides from the four polygons that make up:

$p=3+3+3+4.2+3+6+6=\boxed{28.2\:\text{units}}$

5 0

2 years ago

Who good at the math

Otrada [13]

Im pretty good at Math depending on what type of math it is?

7 0

3 years ago

Cody's Aunt pays him $30 to walk her dogs 6 times at this rate how many times must he walk the dog in order to earn $100

Shkiper50 [21]

20 times
$5 = 1 walk
Divide 100 by 5 and you get 20

5 0

2 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago

Solve the equation, keeping the value for x as an improper fraction. 23x = − 12x + 5 1.Isolate the variable by adding 12x to bot

kogti [31]

Answer:

$x=\frac{30}{7}$

Step-by-step explanation:

We have been given an equation $\frac{2}{3}x=-\frac{1}{2}x+5$ . We are asked to solve our given equation.

First of all, we will add $\frac{1}{2}x$ on both sides of equation to separate x variable on one side of equation.

$\frac{2}{3}x+\frac{1}{2}x=-\frac{1}{2}x+\frac{1}{2}x+5$

$\frac{2}{3}x+\frac{1}{2}x=5$

Now, we will make a common denominator.

$\frac{2*2}{3*2}x+\frac{1*3}{2*3}x=5$

$\frac{4}{6}x+\frac{3}{6}x=5$

Add numerators:

$\frac{4+3}{6}x=5$

$\frac{7}{6}x=5$

Upon multiply both sides of our equation by $\frac{6}{7}$ , we will get:

$\frac{6}{7}*\frac{7}{6}x=5*\frac{6}{7}$

$x=\frac{5*6}{7}$

$x=\frac{30}{7}$

Therefore, the solution for our given equation is $x=\frac{30}{7}$ .

5 0

3 years ago

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