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4 years ago

The container that holds the water for the football team is

Mathematics

2 answers:

larisa [96]4 years ago

7 0

Can't really understand this question but i'm pretty sure the anwser is 15 gallons

aliya0001 [1]4 years ago

3 0

15 gallons
hope this helps. not really sure what you mean by that.

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2(h - 8) - h = h - 16

tresset_1 [31]

$2(h-8)-h=h-16$

$2h-16-h=h-16$

$h=h$

h has infinitely many solutions.

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3 years ago

F(x)= -5x-1 and g(x)= 2x^2<br>solve (f+g)(x)

Georgia [21]

$f(x)=-5x-1;\ D_f:x\in\mathbb{R}\\\\g(x)=2x^2;\ D_g:x\in\mathbb{R}\\\\D_f=D_g\ then\ (f+g)(x)=f(x)+g(x)\\\\(f+g)(x)=-5x-1+2x^2=2x^2-5x-1$

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3 years ago

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4. Would a 51-foot ladder be long enough to climb a 50-foot wall? Sketch a graph and find your answer using a trigonometric rati

andreyandreev [35.5K]

Answer:

It is

Step-by-step explanation:

Using Pythagoras 51^2 = 50^2 + b^2

b=10.0499

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3 years ago

A batch of 40 parts contains six defects. If two parts are drawn randomly one at a time without replacement, what is the probabi

adell [148]

Answer:

a) Therefore, the probability is P=1/52.

b) Therefore, the probability is P=9/400.

Step-by-step explanation:

We know that a batch of 40 parts contains six defects.

a) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time without replacement.

The probability for the first is 6/40.

The probability for the second is 5/39.

We get:

$P=\frac{6}{40}\cdot \frac{5}{39}\\\\P=\frac{1}{52}$

Therefore, the probability is P=1/52.

b) We calculate the probability that the both parts are defective, if two parts are drawn randomly one at a time with replacement.

The probability for the first is 6/40.

The probability for the second is 6/40.

We get:

$P=\frac{6}{40}\cdot \frac{6}{40}\\\\P=\frac{9}{400}$

Therefore, the probability is P=9/400.

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3 years ago

If 32%=80 what does 100%=

emmasim [6.3K]

32/80 so divide that by 5 = 6.4/20 then multipy that by 100/1 so the answer is 640

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3 years ago

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