Hello,
f(x)=4(x+3)-5=4x+12-5=4x+7
y=4x+7==>c=(y-7)/4
f^(-1)(x)=(x-7)/4
f^(-1)( 3)=(3-7)/4=-4/4=-1
Answer D
Answer:
$261
Step-by-step explanation:
Simply multiply 0.6 by 435
Given:
To find:
The quadrant of the terminal side of 
and find the value of 
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, 
must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.
Answer:
a. We can say that P > C, where 'P' represents Peter's earnings and 'C' represents Cindy's earnings.
Given that P = 3h and C = 2h, where h =$4.50. We can say also that 3h > 2h.
b. If Cindy wants to earn at least $14 a day working two hours. Then:
2h ≥ $14
To solve the problem, we just need to solve for 'h':
h ≥ $7
Therefore, se should earn more or equal to $14 per hour.
Answer: 234
Step-by-step explanation: 78 * 3 = 210 + 24 = 234
