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nlexa [21]
3 years ago
8

What is he total coast to print exactly 15 copies?

Mathematics
1 answer:
artcher [175]3 years ago
8 0

You would start by finding out how much 10 and 20 cost per copy

10: 40-25 = 15/10 = $1.50 dollars per copy

20 (This is for checking your math, not required): 55-25 = 30/20 = $1.50 dollars per copy

So, to find 15 copies you would use this formula: 25 + 1.5x

25 + 1.5(15)

25 + 22.5

$47.50 for 15 copies

Now for the second question:

160 - 25 = 135/1.5 = 90 copies

90 copies for $160

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The ages of three friends are consecutive integers. The sum of their ages is 45
Alborosie

45 = (x) + (x + 1) + (x + 2)

45 = 3x + 3

- 3

42 = 3x

/3

14 = x

45 = 14 + (14 + 1) + (14 + 2)

45 = 14 + 15 + 16

The ages of the 3 friends are 14, 15, and 16.

6 0
3 years ago
Read 2 more answers
What is lim x→3 x^2 - x - 6/ x - 3
Kisachek [45]
<h3>Answer: D) 5</h3>

=======================================================

Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
4 years ago
Find the value of x. Round to the nearest tenth.
serg [7]

Answer:

Where is the equation?

Step-by-step explanation:

8 0
3 years ago
hi um can you tell me where i am supposed to put the 2 points? i know that the first one goes on the 0 but where do i but the 2n
Nina [5.8K]

Answer:

114.75

Step-by-step explanation:

You just multiply 25.50 by 4.50 :))

Hope this helps and sorry if I'm wrong.

Have a wonderful rest of your day. <3

8 0
3 years ago
O curso de inglês de Carolina teve duração de 4 semestres e 2 meses . quantos tempo durou esse curso de Carolina ?
Afina-wow [57]

Answer:

a 26 meses gracias por los puntos

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3 years ago
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