1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
krek1111 [17]
3 years ago
9

There are 1,000 fish in a lake. Each year the population declines by 15%, but afterward, the lake is restocked with 500 aditiona

l fish. Write a recursive rule to find the number of fish in the lake for any year
Mathematics
1 answer:
KatRina [158]3 years ago
4 0
We begin with 1,000 fish in a lake.
Each year the population declines to 15%
Then they put back 500 fish in the lake.

The equation: (1000 * .85) +500
You might be interested in
PLWEASE HELPP PLEASEEEEEE CAN U PLS HELP ILL MARK BRAINIEST
Alexus [3.1K]

Answer:

the first one that looks like a star

Step-by-step explanation:

because the shape on the base is a pentagon for the pyramid, and look for another pentagon in the middle of the images in the anwser choice and you find the first one is correct

8 0
3 years ago
Someone plz help i will give brainliest (no links)
WITCHER [35]

Answer:

for part b the answer is 90 degrees

Step-by-step explanation:

2 is adjacent from 5 so they are the same degree number

8 0
2 years ago
If P(not A) = 0.18 and P(A and B) = 0.44, what is P(B given A)?
pickupchik [31]

p(not A)=0.18

p(A&B)= 0.44

A= 0.44- 0.18

  = 0.26

P(B given A)= 0.26+0.18+0.44

                    =0.7

3 0
2 years ago
Gunther's starting weight is 248 pounds, and he plans to lose 2 pounds each week. Use a linear equation to determine Gunther's w
n200080 [17]

Answer:

......

Step-by-step explanation:

With these types of problems, it's best to label the unknowns and figure out an equation for what we want to find. Here, we're interested in weight in pounds, which I'll call W, as a function of the number of weeks that have gone by, which I'll call n. So if we can get an equation that relates W to n, we can answer the question of "how many weeks to reach 175 pounds?" by plugging in W = 175 to our equation and solving to find out what value of n gives us that.

Suppose Alex weighs P pounds at the start of his diet. We don't know what P is yet, but we'll aim to find its value later with the information the question gives us.

After 1 week, Alex will lose 2 pounds and will weigh P - 2 pounds

After 2 weeks, Alex will lose another 2 pounds and weigh (P - 2) - 2 = P - 4 pounds

After 3 weeks, Alex will weigh (P - 4) - 2 = P - 6 pounds

You can see the pattern here: after every week, knock off 2 pounds. So in general after n weeks, Alex will lose 2n pounds from his start weight, and he will weigh P - 2n

That gives the equation W = P - 2n, or equivalently

W = -2n + P

We can recognize this as a linear equation, which takes the form y = mx + b, where:

- x is the independent variable,

- y is the dependent variable (the thing that changes as a function of x),

- m is the slope (how much y changes for every unit change in x), and

- b is the y-intercept (that is, the value of y when x = 0).

In our equation W = -2n + P, the number of weeks n is the independent variable, weight W is the dependent variable (it varies as a function of the number of weeks), -2 is the slope (because Alex weight 2 pounds less for every week that goes by), and P - whose value we don't know yet - is Alex's starting weight (i.e., the value of W when n = 0).

To find the value of P, we can use the information in the question that after 6 weeks, Alex weighs 205 pounds. In other words, when n = 6, W = 205. Plug that into our equation and get:

205 = P - 2*6

We can solve that for P:

205 = P - 12

Add 12 to both sides:

P = 205 + 12 = 227

So Alex weighs 227 pounds when he starts the diet, and we have

W = -2n + 227

This is the linear equation the question is asking for.

To find how many weeks Alex needs to reach his target weight of 175 pounds, set W = 175 in the equation and solve it for n:

175 = -2n + 227

Move the -2n over to the other side:

2n + 175 = 227

Subtract 175 from both sides:

2n = 227 - 175

2n = 52

Divide both sides by 2:

2n/2 = 52/2

n = 26

So if he keeps losing 2 pounds per week, Alex will reach his target weight of 175 pounds after 26 weeks.

Of course in real life weight loss doesn't necessarily work like in this question (usually, the rate of loss slows down closer to the goal and the body adapts to eating less). But for the purposes of this question and with this simple linear model of weight loss, Alex would reach his goal weight in half a year.

8 0
2 years ago
The Cartesian coordinates of a point are given. (a) (−3, 3) (i) Find polar coordinates (r, θ) of the point, where r > 0 and 0
irina [24]

Answer:

a) (-3, 3)

(i) Polar coordinates (r, θ) of the point, where r > 0 and 0 ≤ θ < 2π. (r, θ)

= (3√2, 0.75π)

(ii) Polar coordinates (r, θ) of the point, where r < 0 and 0 ≤ θ < 2π. (r, θ)

= (-3√2, 1.75π)

b) (4, 4√3)

(i) Polar coordinates (r, θ) of the point, where r > 0 and 0 ≤ θ < 2π. (r, θ)

= (8, 0.13π)

(ii) Polar coordinates (r, θ) of the point, where r < 0 and 0 ≤ θ < 2π. (r, θ)

= (-8, 1.13π)

Step-by-step explanation:

We know that polar coordinates are related to (x, y) coordinates through

x = r cos θ

y = r sin θ

And r = √[x² + y²]

a) For (-3, 3)

(i) x = -3, y = 3

r = √[x² + y²] = √[(-3)² + (3)²] = √18 = ±3√2

If r > 0, r = 3√2

x = r cos θ

-3 = 3√2 cos θ

cos θ = -3 ÷ 3√2 = -(1/√2)

y = r sin θ

3 = 3√2 sin θ

sin θ = 3 ÷ 3√2 = (1/√2)

Tan θ = (sin θ/cos θ) = -1

θ = 0.75π or 1.75π

Note that although, θ = 0.75π and 1.75π satisfy the tan θ equation, only the 0.75π satisfies the sin θ and cos θ equations.

So, (-3, 3) = (3√2, 0.75π)

(ii) When r < 0, r = -3√2

x = r cos θ

-3 = -3√2 cos θ

cos θ = -3 ÷ -3√2 = (1/√2)

y = r sin θ

3 = -3√2 sin θ

sin θ = 3 ÷ -3√2 = -(1/√2)

Tan θ = (sin θ/cos θ) = -1

θ = 0.75π or 1.75π

Note that although, θ = 0.75π and 1.75π satisfy the tan θ equation, only the 1.75π satisfies the sin θ and cos θ equations.

So, (-3, 3) = (-3√2, 1.75π)

b) For (4, 4√3)

(i) x = 4, y = 4√3

r = √[x² + y²] = √[(4)² + (4√3)²] = √64 = ±8

If r > 0, r = 8

x = r cos θ

4 = 8 cos θ

cos θ = 4 ÷ 8 = 0.50

y = r sin θ

4√3 = 8 sin θ

sin θ = 4√3 ÷ 8 = (√3)/2

Tan θ = (sin θ/cos θ) = (√3)/4

θ = 0.13π or 1.13π

Note that although, θ = 0.13π and 1.13π satisfy the tan θ equation, only the 0.13π satisfies the sin θ and cos θ equations.

So, (4, 4√3) = (8, 0.13π)

(ii) When r < 0, r = -8

x = r cos θ

4 = -8 cos θ

cos θ = 4 ÷ -8 = -0.50

y = r sin θ

4√3 = -8 sin θ

sin θ = 4√3 ÷ -8 = -(√3)/2

Tan θ = (sin θ/cos θ) = (√3)/4

θ = 0.13π or 1.13π

Note that although, θ = 0.13π and 1.13π satisfy the tan θ equation, only the 1.13π satisfies the sin θ and cos θ equations.

So, (4, 4√3) = (-8, 1.13π)

Hope this Helps!!!

8 0
3 years ago
Other questions:
  • Solve the proportion of 2/v = 4/6
    6·1 answer
  • What is the sum of the geometric series
    8·1 answer
  • What is the vertex (x,y)? h(t)=2x^2+4x+7<br> PLS SHOW WORK
    6·1 answer
  • Jayce sold 218 cups of lemonade at his lemonade stand. What is 218 rounded to the nearest ten?
    6·2 answers
  • What is Coordinate rotation
    15·1 answer
  • What is the sine ratio for
    8·1 answer
  • Marina correctly simplified the expression StartFraction negative 4 a Superscript negative 2 Baseline b Superscript 4 Baseline O
    9·1 answer
  • A copy machine makes 36 copies per minute. How long does it take to make 117 copies
    15·2 answers
  • The inequality log8(2x) &lt; log2(x – 2) can be graphed on the graphing calculator by using the inequalities log8(2x) &lt; y and
    12·1 answer
  • Please help asap thank you!!!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!