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babymother [125]
3 years ago
7

The basketball coach made up a game to play where each player takes 10 shots at the basket. For every basket made, the player ga

ins 10 points.For every basket missed, the player loses 15 points. The player with the lowest score sank 2 baskets and missed 8 what was the lowest score
Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
Every basket he made: 10 points × 2 times = 20 points
He missed : 15 points × 8 times = 120 points
The answer: 20 - 120 = -100 points
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What is the diameter of a circle with a circumference of 23.55m?​
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Answer:

C= π x diameter

diameter = c/π

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23.55/3.14 = 7.5 m

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two times a number is subtracted from 25 the result is the same as when it is added to six times.find the number​
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6.3

Step-by-step explanation:

1. 25 - 2n = n + 6

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3 years ago
What is 9999 times 886 + 234
barxatty [35]

9999*886+234

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3 years ago
Read 2 more answers
The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly sel
garri49 [273]

Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

Answer:

(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

SE = 0.298

Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

5 0
3 years ago
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