Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Answer: -101/18
Step-by-step explanation: I think, I don’t know
29 = 160 - x
x = ?
160 - 29 = 131
SO x = 131
Check:-
160 - 131 = 29
SO,
29 = 160 - 131.
Hope i helped ya!
Since I don't see attachment, I guess the solution will be as follows:
1 & 3/4 , since 1 = 4/4, then it could be rewritten :
4/4 & 3/4, hence between these 2 fraction there is 2/4 or 1/2.
