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hodyreva [135]
2 years ago
6

Y = 2x + 3 y = 3x - 1

Mathematics
1 answer:
lilavasa [31]2 years ago
3 0

Answer:

 x= 4 and y= 11

Step-by-step explanation:

The problem to solve is:

y = 2x + 3 (equation 1)

y = 3x - 1 (equation 2)

Since y = 3x - 1 Solve x from equalution 1

3x - 1 = 2x + 3

3x - 2x = 3 + 1

x = 4

Since x is 4, solve for y

y  = 3x - 1

y = 3(4) - 1

y = 12 -1

y = 11

x =4 and y =7

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6 0
3 years ago
Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

4 0
2 years ago
Use the law of cosines to find the value of 2*3*4 cos theta.
daser333 [38]
The law of cosines :

A^2 = B^2 + C^2 - 2BC cos A

2^2 = 3^2 + 4^2 -  2 . 3. 4 cos theta

= 21

hope this helps
3 0
2 years ago
Read 2 more answers
Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
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You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
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7 0
3 years ago
Which equation has no solution?
konstantin123 [22]

Answer:

B) 4x-5-3x=x+5 has no solution.

Step-by-step explanation:

A) 4x+4=4-4x

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8x+4=4

8x=4-4

8x=0

x=0/8

x=0

------------------

B) 4x-5-3x=x+5

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no solution.

------------------------

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x=0/-10

x=0

------------------------

D) 4x+2-x=4+3x-2

3x+2=3x+4-2

3x+2=3x+2

infinitely many solutions.

8 0
1 year ago
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