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diamong [38]
4 years ago
5

A cabin has room for 7 campers and 2 counselors How many cabins are needed for a total of 49 campers and 14 counselors

Mathematics
2 answers:
Lyrx [107]4 years ago
7 0
7 cabins  are needed for 49 capers an 14 councelors 


Setler [38]4 years ago
4 0
7 \times ? = 49

7 \times 7 = 49

2 \times ? = 14

2 \times 7 = 14

Both were multiplied by 7 therefore,

7 cabins is needed to fit a total of 49 campers and 14 counselors.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

I hope that helps you out!

Any more questions, please feel free to ask me and I will gladly help you out !

~Zoey
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2 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

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  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
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8 0
3 years ago
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creativ13 [48]

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The given function is

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Interchange x and y.

x = 2y + 4

Solve for y,

x - 4 = 2y

Divide both sides by 2

y =  \frac{x}{2}  - 2

Therefore;

{f}^{ - 1} (x)=  \frac{x}{2}  - 2

3 0
3 years ago
Jennifer earns $8.50 per hour for regular work time and $10.50 per hour for overtime. Last week, Jennifer worked 43 hours of reg
allochka39001 [22]

Answer:

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