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Anuta_ua [19.1K]
3 years ago
5

A rabbit and a turtle were to start a race at the same place. The rabbit was asleep when the turtle started. He slept for seven

hours before he started the race. The rabbit's average rate when he was awake was 5 km/hr. The turtle never stopped for a break, but his pace was only 1km/hr. How long will the rabbit run before it catches the turtle?
Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0
Rabbit: y=5x-7
Turtle: y=x

use substitution

x=5x-7
-4x=-7
x=7/4=1.75

1.75hr

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Could ΔABC be congruent to ΔADC by SSS? Explain.
Vera_Pavlovna [14]
There are 5 ways to test if two figures are congruent, namely;
side-angle-side(SAS)
Angle-side-angle (ASA)
Angle-angle-side(AAS)
Hypotenuse-leg (HL)
3 Sides (SSS)
here we shall focus on SSS. When the three corresponding sides of 2 figures say a triangle have the same length we will conclude that the triangles are congruent by SSS.
Therefore from our choices we can conclude that   triangles ABC and ADC are only congruent if the two other side have the same length and BC=DC.

The answer is yes;
B] Yes, but only if BC=DC
6 0
3 years ago
Read 2 more answers
Help pleaseeee thank you
fenix001 [56]

Answer:

Can't read the picture. Please take a bigger picture of the triangle.

8 0
3 years ago
One more time!
CaHeK987 [17]
Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}

so we conclude that
q(\frac{\sqrt{19} }{2} ) = 1/4

therefore

p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right)  \right)

plug x=\sqrt{19}/2 into p( q(x) ) to get answer

p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left(  \frac{\sqrt{19} }{2}\right)^2 }{ \left(  \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow

\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow  -\dfrac{6\sqrt{19} }{361}

p(1/4) = -\dfrac{6\sqrt{19} }{361}
3 0
3 years ago
PLEASE ASAP ILL GIVE BRAINLIEST.
kaheart [24]
I’m going to say the top one it seems like that would be correct
6 0
3 years ago
Read 2 more answers
To wash a window that is 12 feet off the ground, Wayne leans a 13-foot ladder against the
AlladinOne [14]

Answer:

5 meters

Step-by-step explanation:

Based on the situation, it forms into a right triangle. So we will apply the Pythagorean Theorem here. The ladder acts as the hypotenuse while the height from the ground to the window serves as our side "a". We are tasked to solve for "b". Side "b" is the distance from foot of side a to the tip of side c which is the hypotenuse (ladder). We will derive the formula below to solve for b.

c = √( a² + b² )

c² = a² + b²

b² = c² - a²

b = √ ( c² - a² )

b = √ ( 13² - 12² )

b = 5 meters

Correct me if I'm wrong. I hope it helps.

3 0
3 years ago
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