6. three kids and four adults
Answer:
5, 29 will both blank boxes
Step-by-step explanation:
the product of (4z^2 + 7z – 8) and (–z + 3)
(4z² + 7z – 8)(–z + 3)
-z(4z² + 7z – 8) + 3(4z² + 7z – 8)
-4z³-7z²+8z+12z²+21z-24
choose like terms
-4z³-7z²+12z²+8z+21z-24
-4z³+5z²+29z-24
5, 29
This problem is basically
If I plug in n = 16 and r = 9
So there are 4151347200 different nine player batting orders that can be chosen from a baseball team of 16 :)
GCF is 5m^2 n^2
m^2 has exponent 2 and n^2 has exponent 2
(1) m^5n^5
here there is no 5 so it does not have GCF
(2) 5m^4n^3
m^4 has exponent 4 greater than exponent 2
n^3 has exponent 4 greater than exponent 2
5m^4n^3 have GCF
(3) 10m^4n
10 is 5*2 . it has GCF 5
m^4 has exponent 4 greater than exponent 2
n has exponent 1 less than exponent 2
10m^4n does not have GCF
(4) 15m^2n^2
15 is 3*5 which has GCF 5
m^2 has exponent 2 which is equal to exponent 2
n^2 has exponent 2 which is equal to exponent 2
15m^2n^2 have GCF
(5) 24m^3n^4
24 is 2*2*2*3 does not have GCF
m^3 has exponent 3 greater than exponent 2
n^4 has exponent 4 greater than exponent 4
24m^3n^4 does not have GCF
