Answer:
Jose had 60 cards
Phillipe had 15 cards
Step-by-step explanation:
Let the number of trading cards Phillipe had be x. Jose had 4 times, meaning he has 4x of these cards.
Jose gave away 50 cards while Phillipe gave away 5 cards to make their numbers equal.
Mathematically:
4x - 50 = x - 5
3x = 45
x = 45/3 = 15
Phillipe had 15 cards while Jose had 15(4) = 60 cards
No it won’t work sorry for the concierge room
Answer:
C. y = x - 4
Step-by-step explanation:
If you input the value x, than the output y will equal the value y in the table.
If it helps you any
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

so.. check coefficients C and B for the horizontal shift