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2 years ago

Find the value of 9u-2 given that -7u-7=7 ?

Mathematics

2 answers:

kupik [55]2 years ago

6 0

Hey there!

-7u - 7 = 7

ADD 7 to BOTH SIDES

-7u - 7 + 7 = 7 + 7

CANCEL out: -7 + 7 because it give you 0

KEEPs 7 + 7 because it help solve for the u-value

NEW EQUATION: -7u = 7 + 7

SIMPLIFY IT!

-7u = 14

DIVIDE -7 to BOTH SIDES

-7u/-7 = 14/-7

CANCEL out: -7/-7 because it give you 0

KEEP: 14/-7 because it give you the

u-value

NEW EQUATION: u = 14/-7

SIMPLIFY IT!

u = -2

SOLVING FOR : 9u - 2

9u - 2

= 9(-2) - 2

= -18 - 2

= -20

Therefore, your answer is: -20

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Yuliya22 [10]2 years ago

4 0

Answer:

-20

Step-by-step explanation:

when you solve: -7u-7=7, you get u= -2 and when you plug it in you get this equation 9(-2)-2=?

then you get -20

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The answer to this problem?

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The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$