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kolbaska11 [484]
3 years ago
13

Problem: a circle is inscribed in a square. The squares perimeter is 16 times the square root of 6. What is the probability of s

electing a point that is outside the circle??
•please explain and show steps in detail on how to solve for the correct answer

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
I got 21% at selecting a point outside.
Explanation: Since the perimeter is 16sqrt (6), each side must be 4sqrt (6)
This also means that the diameter is 4sqrt (6).

To find the area of a circle, we need to find the radius (2sqrt (6)).
Area of circle is pi × (2sqrt (6))^2 = 24pi or approximately 75.4 units^2
Area of square is 4sqrt (6)^2 = 96

Thus, let's take the area of the circle and subtract that from the area of our square to yield approx. 20.6 units^2
and now divide through by 96 to yield 21%
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Ludmilka [50]
 It would be about 76 years.
6 0
3 years ago
A polynomial has been factored, as shown below: f(x) = (x − 6)(x + 5)(x − 9) What are the zeros of the polynomial? (5 points)
soldi70 [24.7K]

<span>x=6</span>, <span>x=−5</span> or <span>x=9</span>

Explanation:

<span><span>f<span>(x)</span></span>=<span>(x−6)</span><span>(x+5)</span><span>(x−9)</span></span>

If all of the linear factors are non-zero, then so is their product <span>f<span>(x)</span></span>.

If any of the linear factors is zero, then so is their product <span>f<span>(x)</span></span>.

5 0
3 years ago
X + 3/2 = 3/4 (x - 1/2)
Iteru [2.4K]

this would be your answer, <em>x = 1 - 15/2.</em>

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8 0
3 years ago
1. The US Mint has a specification that pennies have a mean weight of 2.5g. From a sample of 37 pennies, the mean weight is foun
Evgesh-ka [11]

Answer:

the pennies does not conform to the US mints specification

Step-by-step explanation:

z = (variate -mean)/ standard deviation

z= 2.5 - 2.4991 / 0.01648 = 0.0546

we are going to check the value of z in the normal distribution table, which is the table bounded by z.

checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)

we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim

since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification

the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected

7 0
3 years ago
The second side of a triangular deck is 4 feet longer than the shortest side, and the third side is 4 feet shorter than twice th
xxTIMURxx [149]
We don’t know the value of the shorter side, so we will categorize it as x. Side 2 is just 4 feet longer than x, so we would add 4 on to it. Side 3 has double the x, so we would multiply it be 2 for 2x, and subtract the 4 feet from it.

Side 1: x
Side 2: x + 4
Side 3: 2x - 4

If the perimeter is 64 feet, then all of the sides have to add up to it. Therefore, first we add all of the side lengths up:

x + x + 4 + 2x - 4 = 4x.

Now we put 4x, the amount of all these sides added up, equal to the perimeter of 64.

4x = 64. Divide both sides by 4 to get x by itself.
x = 16.

Now that we know x is 16, we will substitute it in for all the side lengths’ equations.

We know that Side 1 was just x, so that will be 16. Since Side 2 was 4 more than x, we’d do 16 + 4 = 20. We substitute 16 in for x in Side 3’s equation: 2(16) - 4 = 32 - 4 = 28.

Therefore, the final lengths of all the sides are:

Side 1: 16
Side 2: 20
Side 3: 28
5 0
3 years ago
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