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Nuetrik [128]
3 years ago
12

The height of a cylinder is 5 centimeters. The circumference of the base of the cylinder is 16 centimeters. Find the lateral sur

face area of the figure. Draw the figure if it will help you visualize.
Mathematics
1 answer:
ad-work [718]3 years ago
8 0

The lateral surface area of the cylinder = 80 sq cm.

Step-by-step explanation:

Given,

The circumference of the base of the cylinder is 16 cm

So, 2 X pi X r = 16 cm ( where r be the radius of the base)

Now, the lateral surface of the cylinder = 2 X pi X r X H ( where H be the height = 5 cm)

= 16 X 5 sq cm

= 80 sq cm

Hope it helps you.

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Step-by-step explanation:

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Answer:

B.  \:  \boxed{66.8}

Step-by-step explanation:

to \: solve \: this \: little \: poblem : we \:apply \: the \: pythagrean \: rule \to \\  \boxed{SOH} \boxed{CAH} \boxed{TOA} \to \\ we \: are \: been \: given :  \to \\ the \:  \boxed{opp }\: of \: the \: required \: angle \:  = 35. \\ the \:  \boxed{adj }\: of \: the \: required \: angle \:  = 15. \\  now \: lets \: apply \: \boxed{TOA}\to \: \tan( \theta)  =  \frac{opp}{adj}   \to\\  \tan( \theta)  =  \frac{opp}{adj}  =  \frac{35}{15}  = 2.3333333333 \\  \theta =  \tan {}^{ - 1} (2.3333333333)  \\   \boxed{\theta = 66.80}

♨Rage♨

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