Assume that 10 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.. . What is
the probability that one is hired and one is not?
1 answer:
Possible outcomes: 10C4 = 210 ( combinations - we choose 4 of 10 people )
Favorable outcomes: ( 2C1 ) · ( 8C3 ) = 2 · 56 = 112
Probability : 112 / 210 = 0.5333 ( or 53.33 % ).
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Answer: yes
Step-by-step explanation:
Answer:
6y - 3y - 7 = -2 +3
Simplify both sides:
3y -7 = 1
Add 7 to both sides:
3y = 8
Divide both sides by 3:
y = 8/3 = 2 2/3
There is only one solution.
40 goes into 32 0 times 40 goes into 321 8 times 40 times 8 equls 320 so 8r1
line up your decimals and then multiply like usual, next count how many places after the decimal your problem(s) was and place it to your answer
8 costs 40 so 10 costs | 40 / 8 = ( 5*2=10) So your answer is 50 Dollars.
