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alexira [117]
2 years ago
10

Assume that 10 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.. . What is

the probability that one is hired and one is not?
Mathematics
1 answer:
skelet666 [1.2K]2 years ago
5 0
Possible outcomes: 10C4 = 210  ( combinations - we choose 4 of 10 people )
Favorable outcomes: ( 2C1 ) · ( 8C3 ) =  2 · 56 = 112
Probability : 112 / 210 = 0.5333  ( or 53.33 % ).
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2.8-4.4n-2n+7<br><br><br><br> QUICKLY BRAINLY IF CORRECT
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Step-by-step explanation:

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just add them together as easy as that

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Parallelogram ABCD is shown.<br>​
hichkok12 [17]

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Step-by-step explanation:

#4 part A= D

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Round 2,795 to the nearest ten
Ahat [919]

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6 0
2 years ago
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How many positive integers $n$ from 1 to 5000 satisfy the congruence $n \equiv 5 \pmod{12}$?
irga5000 [103]
The equivalence n \equiv 5 \pmod{12}

means that n-5 is a multiple of 12.

that is

n-5=12k, for some integer k

and so

n=12k+5


for k=-1, n=-12+5=-7

for k= 0, n=0+5=5 (the first positive integer n, is for k=0)


we solve 5000=12k+5 to find the last k

12k=5000-5=4995

k=4995/12=416.25

so check k = 415, 416, 417 to be sure we have the right k:

n=12k+5=12*415+5=4985

n=12k+5=12*416+5=4997

n=12k+5=12*417+5=5009


The last k which produces n<5000 is 416


For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,

thus there are 417 integers n satisfying the congruence.


Answer: 417

6 0
3 years ago
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