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Advocard [28]
3 years ago
15

Which situation CANNOT be represented by this equation?  8x + 5 = 29. this is the first situation:Angel has $29 to order shirts

online. Each shirt costs $5, and there is an $8 shipping charge. How many shirts, x, can Angel buy?
Angel has $29 to order shirts online. He buys 8 shirts and pays a $5 shipping charge. What is x, the cost of each shirt?

Angel is ordering shirts that cost $8 each online. There is also a $5 shipping charge. If he has $29 to spend, how many shirts, x, can he buy?
Mathematics
2 answers:
Ivahew [28]3 years ago
5 0

Answer: The first situation

Step-by-step explanation:

First, let's isolate the x in the equation:

8x+5=29\\8x=29-5\\x=\frac{29-5}{8}

x=3

If you want to calculate the cost of each shirt, that would be: the money that Angel has, minus the shipping charge, divided by the number of shirts that he bought.

If you want to calculate the number of shirts that Angel could buy, that would be: the money that Angel has, minus the shipping charge, divided by the cost of each shirt.

Then, for the second situation:

The money that Angel has is 29, the shipping charge is 5, and the number of shirts is 8. So the situation can be perfectly represented by the equation.

For the third situation:

The money that Angel has is 29, the shipping charge is 5, and the cost of each shirt is 8. So the situation can be perfectly represented by the equation.

The first situation is the only one that can't be represented by the given equation because:

The money that Angel has is 29, the shipping charge is 8 and the cost of each shirt is 5. If you substract the money that Angel has, minus the price of each shirt and then divide by the shipping charge you will not get the number of shirts that he can buy.

REY [17]3 years ago
4 0
He can buy 3 shirts
x=3
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fomenos
Area of semicircle: pi * r^2/2
r = 9/2 = 4.5
3.14 * 4.5^2 = 63.585/2 = 31.7925
Area of middle section:
Make it a rectangle: L * W
9 * 12 = 108
Area of bottom: L * W
6 * 9 = 54
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8 0
3 years ago
Question 1
Cerrena [4.2K]
#1) 4 weeks, $280
#2) (5, 38)
#3) (1, 3)
#4) Step 3
#5) (y+z=6)*-8
#6) 2x+2y=8

Explanation
#1) Setting them equal,
60x+40=50x+80

Subtract 50x from both sides:
60x+40-50x=50x+80-50x
10x+40=80

Subtract 40 from both sides:
10x+40-40=80-40
10x=40

Divide both sides by 10:
10x/10 = 40/10
x=4

Plugging this in to one of our equations,
60(4)+40=240+40=280

#2) Setting the equations equal to one another, 
8x-2=9x-7

Subtract 8x from both sides:
8x-2-8x=9x-7-8x
-2=x-7

Add 7 to both sides:
-2+7=x-7+7
5=x

Plugging this in to the first equation,
8(5)-2=y
40-2=y
38=y

#3) Substituting our value from the second equation into the first one,
n-2+3n=10

Combining like terms,
4n-2=10

Add 2 to both sides:
4n-2+2=10+2
4n=12

Divide both sides by 4:
4n/4 = 12/4
n=3

Substitute this into the second equation:
m=3-2=1

#4) The mistake was made on Step 3; the 4 was left off when the equations were added.

#5) To eliminate y, we want the coefficients to be the same.  To accomplish this, we will multiply the first equation by -8.

#6) In order to have infinitely many solutions, we want each coefficient as well as the constant to be a multiple of our equation.  Multiplying the equation by 2, we get 2x+2y=8.
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