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Y_Kistochka [10]
3 years ago
13

Find the quadratic polynomial if zeros of it are 2 and 1/3 respectively​

Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

\boxed{\sf \ \ \ 3x^2-7x+2 \ \ \ }

Step-by-step explanation:

Hello,

There are a lot of polynomials which have 2 and 1/3 as zeroes,

I can show you one below

3(x-2)(x-\dfrac{1}{3})=(x-2)(3x-1)=3x^2-x-6x+2=3x^2-7x+2

hope this helps

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a car travels along a straight road heading east for one hour, then traveling for 30 minutes on another road that leads northeas
My name is Ann [436]

Answer:

55.96 miles

Step-by-step explanation:

Distance = Speed X time

Car first moved east for 1 hr , distance = 40 x 1 = 40 miles

Car then moved north-east for 30 min, distance = 40 x 0.5 = 20 miles

From trigonometry,

sin 45 = \frac{y}{20} ; y = 20 sin 45 ; y= 14.14 miles

cos 45 = \frac{x}{20} ; x = 20 cos 45 ; x = 14.14 miles

using Pythagoras theorem;

z^{2} = y^{2} + (40+x)^{2}

    = 14.14^{2} + (40+14.14)^{2}

     = 3131.08

z^{2} = \sqrt{3131.08}

z = 55.96 miles

6 0
3 years ago
The large Magellanic Cloud is a galaxy that orbits our milky way galaxy at a distance of 1.79 × 10^5 light years. which shows th
Softa [21]
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8 0
3 years ago
Can someone please answer this
vlada-n [284]

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3 0
3 years ago
What is the midpoint of EC ?
sergij07 [2.7K]

<u>Given</u>:

Given that the graph OACE.

The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)

We need to determine the midpoint of EC.

<u>Midpoint of EC:</u>

The midpoint of EC can be determined using the formula,

Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})

Simplifying, we get;

Midpoint=(\frac{2(t+p)}{2},\frac{2r}{2})

Dividing, we get;

Midpoint=(t+p,r)

Thus, the midpoint of EC is (t + p, r)

Hence, Option A is the correct answer.

7 0
3 years ago
5) Select the best method to solve the system.
MrMuchimi

Answer:

elimination

Step-by-step explanation:

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