A zebra ran at a speed of 20 feet per second. Which operation should you use to find the distance the zebra ran in 10 seconds?
2 answers:
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I suppose the integral is
The integration region corresponds to a sector of a cirlce with radius 5 subtended by a central angle of π/4 rad. We can capture this region in polar coordinates by the set
Then ,
, and
. So the integral becomes
3b - a = 45
a = 2b + 40
Solve simultaneously.
3b - (2b + 40) = 45
3b - 2b - 40 = 45
b = 45 + 40
b = 95min (1 hour 35 min)
a = 2 (95) + 40
a = 230min ( 3 hour 50 min)
a = 2b + 40
Solve simultaneously.
3b - (2b + 40) = 45
3b - 2b - 40 = 45
b = 45 + 40
b = 95min (1 hour 35 min)
a = 2 (95) + 40
a = 230min ( 3 hour 50 min)