All categories

3 years ago

A zebra ran at a speed of 20 feet per second. Which operation should you use to find the distance the zebra ran in 10 seconds?

Mathematics

2 answers:

Elena-2011 [213]3 years ago

8 0

you would multiply speed by time

20 feet per second times 10 seconds = 200 feet total

Lilit [14]3 years ago

5 0

First, you would cross multiply the equation 20ft/1s = x/10s.
Giving you 200ft/10s.

Your answer would be, 200ft.

I hope this helps!

You might be interested in

Maria received a $90 gift card for a coffee store. She used in buying some coffee that costs $7.81 per pound. After buying the c

sergiy2304 [10]

Answer:

Im not sure but im going to try

Step-by-step explanation:

First you subtract $7.81 from $90 until you get to $50.95 and then you count how many times you subtract and your answer is 5 pounds of coffee.

5 0

3 years ago

Read 2 more answers

Faye Tallity earns simple interest on her savings account. She deposits $1,200 into her account and will have $1,344 after 2 yea

Marat540 [252]

Faye will have $1704.00 total money in her account.
She earned $504.00 interest for 7 years.
(She earned $144 for 2 years, divide in half $72 a year= $72×7=$504

8 0

3 years ago

Complete the question.

makvit [3.9K]

Answer:

Step-by-step explanation:

You are looking for the cross section of ask three circles. This is true for the smallest part, with the number 6 in it.

5 0

3 years ago

The price of the bicycle that Rocco wants to buy is $282. How much will Rocco pay for the bicycle if the state tax rate is 4%?

olasank [31]

Answer:

Rocco payes $292.28

Step-by-step explanation:

Because it is an increase so you put 104% over 100% in fraction form and then you put 282 at the bottom of another part of a fraction then you do 100 divided by 282 and you get 2.82 so then you take that 2.82 and you multiply it by 104% and you get 292.28 you can use a calculator to check but i know i did it correctly

5 0

3 years ago

In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it

gavmur [86]

Answer:

a) $P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b) $P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c) A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

Purchased Gum Kept the Money Total

Students Given 4 Quarters 25 14 39

Students Given $1 Bill 15 29 44

Total 40 43 83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}$

And if we replace we got:

$P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341$

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

$P(A|B) =\frac{P(A and B)}{P(B)}$

We have that $P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}$

And if we replace we got:

$P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659$

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0

4 years ago