To find the gradient of the perpendicular line, we know that we must do the negative inverse of the current line's gradient
-6x from the old line will now be 1/6x
we are given points on that line and we therefore use the points and the new gradient to find the equation of the line using this formula
y-y1=m(x-x1) where m is the gradient
input the values that we have
y-5=1/6(x--4)
rearrange
y-5=1/6(x+4)
y-5=1/6x+4/6
6y-30=x+4
6y=x+34
y=1/6x+34/6
y=1/6x+17/3
I believe it would be A 0to 5
Answer:
B
Step-by-step explanation:
Since x = - 2 is the line of reflection then the coordinates of the image will be the same distance in the x- direction from x = 2 but on the opposite side.
The y- coordinates of the points remain unchanged.
D is 3 units left of x = - 2 thus D' is 3 units to the right of x = - 2
E is 1 unit left of x = - 2 thus E' is 1 unit to the right of x = - 2
F is 1 unit left of x = - 2 thus F' is 1 unit to the right of x = - 2
G is 3 units left of x = - 2 thus G' is 3 units to the right of x = - 1
Thus
D(- 5, 5 ) → D'(1, 5 )
E(- 3, 3 ) → E'(- 1, 3 )
F(- 3, - 4 ) → F'(- 1, - 4 )
G(- 5, - 2 ) → G'(1, - 2 )
Answer:
no solution
Step-by-step explanation:
Divide by 4:
3d -1 = 3d
Subtract 3d:
-1 = 0 . . . . . . FALSE
There is no value of d that will make this be true. The equation has NO SOLUTION.
Answer:
7 miles
Step-by-step explanation:
Distance = Rate times Time
Distance #1: (15 mph)(12/60 hr) = 3 miles
Distance #2: (12 mph)(20/60 hr) = 4 miles
Total distance ridden = 7 miles