Answer:
YES
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
<h3>
Answer: 5/12 (choice C)</h3>
Explanation:
Recall that tangent = opposite/adjacent.
For reference angle M, the side ON = 5 is the opposite side and MN = 12 is the adjacent side. We don't need the hypotenuse.
First add the ratio 1:3:5 together to give you the total number:
1 + 3 + 5 + = 9
Therefore you divide 72 by 9 to give you one part
72 divide 9 = 8
Now you times each part of the ratio by 8:
1 x 8 = 8
3 x 8 = 24
5 x 8 = 40
Therefore the answer would be written like this:
8:24:40
Hope this helps
