Answer:
c is all the points in the open interval (0,25)
Step-by-step explanation:
Here given is a function
, which is continuous in the interval [0,25] and differentiable in (0,25)
Mean value theorem says there exists at least one c in the interval (0,25) such that

We have

For the given function

Hence we have c equals all the points in the open interval (0,25)
The answer is answer choice 3
Distribute 7 to both n and 1
7(n + 1) = 7n + 7
5n + 7 = 7n + 7 - 2n
Combine like terms
5n + 7 = 7n - 2n + 7
5n + 7 = 5n + 7
If you want to solve for n, subtract 7 from both sides
5n + 7 (-7) = 5n + 7 (-7)
5n = 5n
then divide 5 from both sides
5n/5 = 5n/5
n = n
Effectively, this equation is <em>unsolvable</em>
hope this helps
Answer:
hi
Step-by-step explanation:
for example

in the second one you should multiple 5 and 1 then add 4