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jarptica [38.1K]
4 years ago
14

One hundred 50 cent coins have a mass of 690g. What is the mass of one 50 cent coin?

Mathematics
2 answers:
Nadya [2.5K]4 years ago
7 0
You divide 690 by 100 which is 6.9
Therefore, one 50cent coin is 6.9g
djyliett [7]4 years ago
4 0
The mass of one 50-cent coin is 6.9g.

690 / 100 = 6.9
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Which graph represents the same relation as the set {(-3,2).(5,5) (3,3), (3,-2)}?
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iogann1982 [59]

Answer:

1) The value of x= 0.0642

2) sin\theta=\frac{P}{H}=\frac{24}{25}

cos\theta=\frac{B}{H}=\frac{7}{25}

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Step-by-step explanation:

1) Given : A right angle triangle with sides x and 10 and angle is 50°

To find : Value of x

Solution : Since, it is a right angle triangle

Therefore, we apply cos\theta=\frac{B}{H}

Where Base = x, Hypotenuse= 10, angle = 50°

cos(50)=\frac{x}{10}

0.642=\frac{x}{10}

0.0642=x

The value of x= 0.0642

2) Given : sec\theta=\frac{25}{7}

To find : Value of sin\theta,cos\theta,tan\theta,cosec\theta,cot\theta

Solution : We have given sec\theta=\frac{25}{7}

sec\theta=\frac{H}{B}

so, B= 7 , H=25

By Pythagoras theorem,

H^2=P^2+B^2

25^2=P^2+7^2

625-49=P^2

\sqrt{576}=P^2

P=24

Now, P=24, B=7, H=25

sin\theta=\frac{P}{H}=\frac{24}{25}

cos\theta=\frac{B}{H}=\frac{7}{25}

tan\theta=\frac{P}{B}=\frac{24}{7}

cosec\theta=\frac{H}{P}=\frac{25}{24}

cot\theta=\frac{B}{P}=\frac{7}{25}



5 0
3 years ago
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