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3 years ago

Two sets of the sum of a number and eight are added to five times the same number

Mathematics

1 answer:

pantera1 [17]3 years ago

7 0

13+13
That’d be
26!!!!

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Sorry i ment to put 14/15 - 1/3 then put as a fraction in simplest form

Sergio039 [100]

Answer:

Step-by-step explanation:

14/15 - 1/3

= 6/10

In simplest form

= 3/5

7 0

2 years ago

Suppose that y varies directly with x and y=12 when x=-2. What is x when y=-6 Please help me!!

hodyreva [135]

Answer:

x = 1 because when you multiply negative 2 by negative six you get twelve. when you multiply positive one by negative six you get negative six.

8 0

3 years ago

Clare is painting some doors that are all the same size. She used 4 liters of paint to cover 50 doors. How many liters of paint

Alinara [238K]

Answer:

12.5 leters

Step-by-step explanation:

If you take the 4 liters she used to cover 50 doors,

4 0

2 years ago

Read 2 more answers

-x-5y=22&y=-7x+16 solve the system by the substitution method

Kaylis [27]

(3,-5) is your answer .-.

4 0

2 years ago

Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .

Solution :- 

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

$\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ .

We can see that this is in Geometric Progression where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

$\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]$

Notice the term $\dfrac{1}{2^{25}}$ will be too small , so we can neglect it and take its approximation as 0 .

$\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]$

$\\\implies \boxed{ S_1 \approx 1 }$

$\rule{200}2$

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

$\implies S_2=\dfrac{n}{2}[2a + (n-1)d]$

Substitute ,

$\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}$

Hence sum = 908 + 1 = 909

7 0

2 years ago