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IRISSAK [1]
3 years ago
14

Two sets of the sum of a number and eight are added to five times the same number

Mathematics
1 answer:
pantera1 [17]3 years ago
7 0
13+13
That’d be
26!!!!
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Sorry i ment to put 14/15 - 1/3 then put as a fraction in simplest form
Sergio039 [100]

Answer:

Step-by-step explanation:

14/15 - 1/3

= 6/10

In simplest form

= 3/5

7 0
2 years ago
Suppose that y varies directly with x and y=12 when x=-2. What is x when y=-6<br> Please help me!!
hodyreva [135]

Answer:

x = 1 because when you multiply negative 2 by negative six you get twelve. when you multiply positive one by negative six you get negative six.

8 0
3 years ago
Clare is painting some doors that are all the same size. She used 4 liters of paint to cover 50 doors. How many liters of paint
Alinara [238K]

Answer:

12.5 leters

Step-by-step explanation:

If you take the 4 liters she used to cover 50 doors,

4 0
2 years ago
Read 2 more answers
-x-5y=22&amp;y=-7x+16 solve the system by the substitution method
Kaylis [27]
(3,-5) is your answer .-.
4 0
2 years ago
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
2 years ago
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