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3 years ago

Urgent Please Help!!! write an equation of the line that passes through (0, -5) and is perpendicular to the line y = -4/5x

Mathematics

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

y=5/4x-5

Step-by-step explanation:

Perpendicular means negative reciprocal of the slope.

y-y1=m(x-x1)

y-(-5)=5/4(x-0)

y+5=5/4(x)

y+5=5/4x

y=5/4x-5

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Inequalities:

USPshnik [31]

125x + 55 < 555
Okay, subtract 55 from both sides.
125x < 500
Divide by 125 to isolate the x.
125x < 500
/125 /125
x < 4
The school can have the DJ for less than 4 hours, or for 4 hours. Hope that helps.

6 0

4 years ago

PLEASE HELP!!! Blue whales eat an average of 5,000 pounds of fish daily, with a standard deviation of 850 pounds. Approximately

REY [17]

Answer:

15.87% of blue whales eat more than 5,850 pounds of fish

Step-by-step explanation:

Mean = 5000

Standard Deviation = 850

We need to find P(x>5850) = ?

We can find using z-score

z = x - mean/ standard deviation

z = 5850 - 5000/850

z = 850/850

z = 1

Now, P(x>5850) = P(z>1)

Finding value of P(z>1) by looking at the z-score table

P(z>1) = 0.8413

The normal distribution gives area to the left , so subtracting it from 1 to gain the answer

1-0.8413 = 0.1587

Now, to find percentage multiply it with 100

0.1587 * 100 = 15.87 %

15.87% of blue whales eat more than 5,850 pounds of fish

5 0

3 years ago

Read 2 more answers

Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$