Answer:
3 7/12 kg
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Step-by-step explanation:
On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.
Total plant bought = 4 1/2 kg
Strawberry = 1 2/3 kg
Tomato = 1/4 kg
Strawberry + tomato
= 1 2/3 + 1/4
= 5/3 + 1/4
= 20+3/12
= 23/12 kg
Total remaining after Sunday
= Total - used
= 4 1/2 - 23/12
= 9/2 - 23/12
= 54-23/12
= 31/12
= 2 7/12 kg
Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.
Strawberry = 2 × 1 2/3
= 2 × 5/3
= 10/3 kg
Tomato = 1 × 1/4
= 1/4 kg
Total plant needed to feed strawberry two more times and tomato 1 more time
= 10/3 kg + 1/4 kg
= 40+3/12
= 43/12 kg
= 3 7/12 kg
He will need 3 7/12 kg of plant
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Answer:
630
Step-by-step explanation:
4n/4n-4 × n-1/n+1
= 4n(n-1)/(4n-4)(n+1)
= (4n^2 - 4n)/(4n^2 + 4n - 4n-4)
= (4n^2 - 4n)/(4n^2 - 4)
= 4(n^2 - n)/4(n^2 - 1)
=(n^2 - n)/(n^2 - 1)
C the third one
Step by step
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1
Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;
so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
;
