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3 years ago

How many boxes of fish can fit in the shipping box? Explain your answer, will give brainlest!

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Answer:

2340 boxes

Step-by-step explanation:

to find out how many boxes or cans fit there u need to know the volume of the box and the cans or boxes

v= l*w*h

v= volume

l=length

w=width

h=height

first lets find the volume of one can or box of fish food

the length, the width, and the height are the same which is 1/4, so cube 1/4 or 1/4*1/4*1/4

1/4*1/4*1/4= 1/16 *1/4= 1/64

Now u have to find the volume of the shipping box, so the length is 3 3/4, the width is 3, and the height is 3 1/4

3 3/4*3*3 1/4= 15/4*3/1*13/4

15/4*3/1*13/4= 45/4*13/4 = 585/16

now divided the volume of shipping box by the volume of fish food boxes

585/16 divided by 1/64 and now u do the KFC or the keep flip change

u keep the 585/16 and then flip the sign to multiplication and then change the last number to 64/1

585/16 times 64/1= 37440/16 or 2340

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Step-by-step explanation:

Edge of cube = 10

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Read 2 more answers

I need help answering this question please help

MArishka [77]

40

Or at least that what my calculator says.

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Please calculate this limit <br>please help me

Tasya [4]

Answer:

We want to find:

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}$

Here we can use Stirling's approximation, which says that for large values of n, we get:

$n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n$

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}$