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3 years ago

The number of grams in 17 kilograms

Mathematics

1 answer:

klemol [59]3 years ago

4 0

Answer:

17000g

Step-by-step explanation:

17kg to g is multiplied with 1000

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The tiles on the left contain functions written using function notation. Match each function with its input.

Degger [83]

Answer:

1. The input is f

2. The input is g

3. The input is h

Step-by-step explanation:

The value inside the bracket of the function is the input given to the function.

1. g(f) = 2f

The input is f

2. h(g) = -4+g

The input is g

3. f(h) = h - 7

The input is h

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3 years ago

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Find the value of x to the nearest tenth

TEA [102]

Answer:

114

Step-by-step explanation:

You would add 46 degree and 20 degrees (66) and subtract (180 - 66 = ?) to get your answer.

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3 years ago

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In a sample of 70 stores of a certain company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi

uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$n = 70, p = \frac{62}{70} = 0.886$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.

We need at least n stores.

n is found when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}$