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nikdorinn [45]
2 years ago
11

The number of grams in 17 kilograms

Mathematics
1 answer:
klemol [59]2 years ago
4 0

Answer:

17000g

Step-by-step explanation:

17kg to g is multiplied with 1000

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WHat is the missing height?
ololo11 [35]

Answer:

w = 4 cm

Step-by-step explanation:

recall that the area of a triangle is given by

A = (1/2) x base length x height

we are given:

A = 10 cm²

base length = 5 cm

height = w

substituting the values above into the equation,

A = (1/2) x base length x height

10 = (1/2) x 5 x w

20 = 5w

w = 20/5

w = 4 cm

3 0
3 years ago
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Solve the inequality 3(2x+7)>-3+5x.​
lilavasa [31]

Answer:

Check pdf

Step-by-step explanation:

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7 0
3 years ago
Need help. 7.58 × 10^2<br><br> convert with a standard and scientific notation
mixas84 [53]
The answer is 0.00758
7 0
3 years ago
Hannah received $30 for her birthday and bought 3 shirts that were all the same price. If she had $9 left over, which equation s
Natasha2012 [34]
Money spent + money left over = total money

money spent + 9 = 30

We don't know the price of each shirt, so let x = price of 1 shirt.
Then, 3 shirts cost 3 times as much as x, or 3x.
She spent 3x.

3x + 9 = 30
5 0
3 years ago
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How would I find a? What formula would I use?
xenn [34]

Answer:

  You can use either of the following to find "a":

  • Pythagorean theorem
  • Law of Cosines

Step-by-step explanation:

It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.

I find it reasonably convenient to find the length of x using the sine of the 70° angle:

  x = (15 ft)/sin(70°)

  x ≈ 15.96 ft

That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.

__

Consider the diagram below. The relation between DE and AE can be written as ...

  DE/AE = tan(70°)

  AE = DE/tan(70°) = DE·tan(20°)

  AE = 15·tan(20°) ≈ 5.459554

Then the length EC is ...

  EC = AC - AE

  EC = 6.3 - DE·tan(20°) ≈ 0.840446

Now, we can find DC using the Pythagorean theorem:

  DC² = DE² + EC²

  DC = √(15² +0.840446²) ≈ 15.023527

  a ≈ 15.02 ft

_____

You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)

  DC² = AD² + AC² - 2·AD·AC·cos(A)

  a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635

  a = √225.70635 ≈ 15.0235 . . . feet

3 0
3 years ago
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