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OverLord2011 [107]
2 years ago
7

A table has five bowls. None of the quantities in the bowls are prime, though the last two bowls are empty. Two of the quantitie

s are squares, and when added to the remaining number, the sum is 21. What are the amounts in the first three bowls?
Mathematics
1 answer:
Digiron [165]2 years ago
8 0

Since two of the quantities are squares and the sum of all of three is equal 21, then the possible values of those two quantities are: 1,4,9,16

Let's consider each possibility

1 and 4

21-1-4=16, but 16 is also square and there can be only two square so NO

1 and 9

21-1-9=11, but 11 is prime, so NO

1 and 16

21-1-16=4... 4 is a square ,so NO

4 and 9

21-4-9=8 , 8 is not prime and not a square, so YES

4 and 16

21-4-16=1, but 1 is a square ,so NO

9 and 16

9+16=25>21 so.. NO

<u>Therefore, the amounts in the first three bowls are 4,8,9.</u>

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