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OverLord2011 [107]
2 years ago
7

A table has five bowls. None of the quantities in the bowls are prime, though the last two bowls are empty. Two of the quantitie

s are squares, and when added to the remaining number, the sum is 21. What are the amounts in the first three bowls?
Mathematics
1 answer:
Digiron [165]2 years ago
8 0

Since two of the quantities are squares and the sum of all of three is equal 21, then the possible values of those two quantities are: 1,4,9,16

Let's consider each possibility

1 and 4

21-1-4=16, but 16 is also square and there can be only two square so NO

1 and 9

21-1-9=11, but 11 is prime, so NO

1 and 16

21-1-16=4... 4 is a square ,so NO

4 and 9

21-4-9=8 , 8 is not prime and not a square, so YES

4 and 16

21-4-16=1, but 1 is a square ,so NO

9 and 16

9+16=25>21 so.. NO

<u>Therefore, the amounts in the first three bowls are 4,8,9.</u>

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Answer:

x = 2/3 or x = -2/3

Step-by-step explanation:

Solve for x over the real numbers:

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Hint: | Divide both sides by a constant to simplify the equation.

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Hint: | Eliminate the exponent on the left-hand side.

Take the square root of both sides:

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3 years ago
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The surface area of the drum is 3317.5218 square inches.

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Where the first term of the sum is the area of the lid and bottom of the drum and the second term is the area of the walls of the drum, r is the radius and h is the height. Applying the data from the problem, we have:

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The surface area of the drum is 3317.5218 square inches.

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-3 1/2= 1/2x+1/2x+x A)-1 3/4 B)-5 1/2 C)-1 1/2 10points each
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