All categories

3 years ago

Is this a relation: {(-2,1), (0,0), (0,1), (1,-2), (1,0), (1,3), (2,0)}? Explain why or why not.

1 answer:

tatiyna3 years ago

4 0

It is a relation because any relation is simply a set of (x,y) values known as points or ordered pairs. There are no other qualifications needed to be a relation. We simply pair up any x and y value we want.

I think you meant to ask if it's a function or not. If so, then the answer is "no, it is not a function". Why not? Because the x value x = 0 produces more than one y output y = 1 and y = -2. Graph these points and you'll see them fail the vertical line test (ie its possible to draw a vertical line through more than one point on the graph). The same issue happens with (1,-2), (1,0) and (1,3) as well.

In summary:

Yes it is a relation

No it is not a function

The reasoning for each is stated above

You might be interested in

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$

7 0

2 years ago

Which of the following is equivalent to (5)^7/3? 5^-4 5^4 ^7squroot5^3 ^3squroot5^7

kvv77 [185]

Answer:

^7 squroot5^3

Step-by-step explanation:

5x2= 10

7÷ 3= 2.5

8 0

3 years ago

Please answer below :-)

mestny [16]

Answer:

A: 18

Step-by-step explanation:

Hopefully this helps!

3 0

2 years ago

What is the next step you should take? 1 + 18n = 33

Ivahew [28]

Answer:

You need to carry the one over by subtracting 1 from 33. The new equation will be 18n = 32

3 0

2 years ago

Read 2 more answers

What is the value of 2/3(x -6) -y , when x= 9 and y=5/6?

ANTONII [103]

Answer:

Ã=7/6

Step-by-step explanation:

2/3(x -6) -y

<h3>put the value of x= 9 and y=5/6 </h3>

=2/3(9-6)-5/6

=2/3×3-5/6

=2/1-5/6

=12-5/6

=7/6

hey mate hope it's help you......

7 0

2 years ago

Read 2 more answers