I neeeeeeed Help please!

Mathematics

1 answer:

pochemuha3 years ago

4 0

Answer:

i ask your teacher

Step-by-step explanation:

ask your teacher instead of asking for answers

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Rectangle with area of 10 and length of 2 1/2. Whats the width?

Stels [109]

Hello!

We have been given enough information to solve this question!
We know that the length of the rectangle is 2.5, and we also know how to find the area:

A = l × w

But we don't need the area, we need to find the width of the rectangle! You see, we had to multiply the length by the width to find the area.

Now, to find the width, we must flip the problem around and use the opposite of multiplication, which is division.

W = a ÷ l

W = 10 ÷ 2.5

W = 4

Therefore, the width of the rectangle is 4.

3 0

2 years ago

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If ΔOPQ is dilated from point Q by a scale factor of 3, which of the following equations is true about segment R prime S prime?

Sergio [31]

Answer:

$\overline {R'S'} = 3 {\overline {RS} }$

Step-by-step explanation:

The scale factor of dilation of triangle ΔOPQ, S.F. = 3

The center of dilation = Point <em>Q</em>

Therefore;

The length of the segment, ${\overline {S'Q'} }$ = 3 × The length of the segment, ${\overline {SQ} }$

Similarly;

The length of the segment, ${\overline {R'Q'} }$ = 3 × The length of the segment, ${\overline {RQ} }$

By Pythagoras theorem, we have;

${\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2$

Therefore;

${\overline {R'S'} }^2 = {\overline {R'Q'} }^2 - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2 - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} } ^2 - {\overline {SQ} } ^2 \right) = 9 \times {\overline {RS} }^2$