The question is incomplete, here is the complete question:
The perimeter of a rectangle is twice the sum of its length and its width, the perimeter is 40 meters and the length is 2 meters more than twice its width. What is the length?
The length of the rectangle is 14 meters
Step-by-step explanation:
The formula of the perimeter of a rectangle is P = 2(L + W), where
- L is its length
- W is its width
Assume that the width of the rectangle is x meters
∵ The width of the rectangle = x meters
∵ Its length is 2 meters more than twice its width
- Multiply x by 2 and then add to the product 2
∴ The length of the rectangle = 2 x + 2 meters
∵ The formula of the perimeter is P = 2(L + W)
- Substitute L by 2 x + 2 and W by x
∴ P = 2(2 x + 2 + x)
- Add like terms in the bracket
∴ P = 2(3 x + 2)
- Simplify the right hand side
∴ P = 6 x + 4
∵ The perimeter of the rectangle = 40 meters
- Equate P by 40
∴ 6 x + 4 = 40
- Subtract 4 from both sides
∴ 6 x = 36
- Divide both sides by 6
∴ x = 6
∴ The width of the rectangle is 6 meters
∵ The length = 2 x + 2
- Substitute x by 6
∴ The length = 2(6) + 2 = 12 + 2 = 14 meters
The length of the rectangle is 14 meters
Learn more:
You can learn more about the rectangles in brainly.com/question/12919591
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