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valina [46]
3 years ago
6

Tennis balls cost 7$ for a can of 3. Steve gives the cashier $40 to buy balls and receives $12 in change. How many tennis balls

did Steve buy?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
4 cans. 12 tennis balls.
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One of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average
Nonamiya [84]

Answer:

0.0930

Step-by-step explanation:

Given that one of your friends is testing the effect of drinking coffee on the duration of cold symptoms. The common cold lasts, on average, 6 days.

she tests a one-sided alternative about the population mean cold duration when drinking coffee, H0: μcoffee = 6 Ha: μcoffee < 6 She finds z = −1.68 with one-sided P-value P = 0.0465.

If hypotheses changed to two tailed as:

H_0: \mu_{coffee}  = \mu_{tea}\\H_a: \mu_{coffee}\neq \mu_{tea}

(Two tailed test)

Since we have mean difference and std error the same, test statistic would remain the same.

p value for two tailed would be = twice the p value for one tail

=2(0.0465)\\= 0.0930

6 0
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The ages of the 11 players of a soccer team on the soccer field are shown 21,32,22,28,26,30,29,24,22,24,26
bekas [8.4K]

Answer:

B is the answer of the following question...

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7 0
3 years ago
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A mechanic works on the overhaul of a transmission. He starts at 8:25 AM and finishes
Mama L [17]
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If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?
klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0
1 year ago
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Hoochie [10]
6 3/4= 6.75

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Final answer: 540 miles
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