<em><u>The cost of production equation is:</u></em>
C = 10n + 20000
<em><u>Solution:</u></em>
<em><u>The equation representing the cost, C, of producing n tires at Royal Tires Co. can be written as:</u></em>
C = mn + f
Where,
C = cost
n = number of tires
f = company's fixed cost
<em><u>It costs $30,000 to produce 1,000 tires while it costs $50,000 to produce 3,000 tires</u></em>
Therefore,
30, 000 = m(1000) + f
50, 000 = m(3000) + f
Which is,
1000m + f = 30000 ------- eqn 1
3000m + f = 50000 ------- eqn 2
Subtract eqn 1 from eqn 2
3000m + f = 50000
1000m + f = 30000
( - ) -------------------
2000m = 20,000
m = 10
Substitute m = 10 in eqn 1
1000(10) + f = 30000
f = 30000 - 10000
f = 20,000
Thus the equation is:
C = 10n + 20000
5m+2(m+8)+3
5m+2m+16+3
7m+19
Answer:
The mean for the combined sample = 6.
Step-by-step explanation:
We have been given that one sample of n = 10 scores has a mean of M = 8.
So the sum of 10 scores for 1st sample will be: 
We are also told that second sample of n = 5 scores has a mean of M = 2.
So the sum of 5 scores for 2nd sample will be: 
When the both samples are combined, so total points will be:
and total scores will be
.



Therefore, the mean for the combined sample will be 6.
14.
Angles 4 and 6 are supplementary, because they are on the same line. Supplementary angles add up to 180 degrees, and a line must be 180 degrees.
15.
Angles 1 and 8 are congruent, because they are alternate exterior angles
16.
m = y2 - y1 / x2 - x1
m = 7 - 2 / 4 - 5
m = 5 / -1
m = -5
17.
m = 3 - 3 / 7 - (-5)
m = 0 / 12
m = 0
18.
m = 1 - (-2) / 5 - (-4)
m = 3 / 9
m = 1/3
19.
A = (0, 3) - B = (3,0)
m = 0 - 3 / 3 - 0
m = -3 / 3
<em>m = -1</em>
C = (0, -2) - D = (4, 2)
m = 2 - (-2) / 4 - 0
m = 4 / 4
<em>m = 1</em>
Perpendicular, because the slopes are opposite reciprocals.
20.
E = (1, 2) - F = (0, 0)
m = 0 - 2 / 0 - 1
m = -2 / -1
<em>m = 2</em>
G = (1, -3) - H = (3, 0)
m = 0 - (-3) / 3 - 1
<em>m = 3 / 2</em>
Neither, because the slopes are different.
21.
I = (0, 1) - J = (2, -4)
m = -4 - 1 / 2 - 0
<em>m = -5/2</em>
K = (-1, -2) - L = (4, 0)
m = 0 - (-2) / 4 - (-1)
<em>m = 2/5</em>
Perpendicular, because the slopes are opposite reciprocals.
22.
M = (-2, 2) - N = (2, 2)
Horizontal line
<em>m = 0</em>
O = (3, 0) - P = (-3, 0)
Horizontal line
<em>m = 0
</em>Parallel, because the slopes are the same.
<em>
</em>23.
Angle 2 is congruent to angle 1 because of the alternate exterior angle theorem.
Angle 1 is congruent to angle 3 because of the vertical angle theorem.
Angle 2 is congruent to angle 3 because of substitution.
Line l is parallel to line m because the corresponding angles are congruent.