Answer: A
Step-by-step explanation:
To find the inner product of two vectors (a,b) and (c,d) you would use the equation (a * c) + (b * d)
So for (7,2) and (0,-2) the inner product would be
(7 * 0) + (2 * -2)
= 4
The vectors are only perpendicular when the inner product is equal to 0. Since it is equal to -4 in this case, the vectors are not perpendicular.
A -4; no
Answer:
Step-by-step explanation:
Here's how you convert:
![\sqrt[n]{x^m}=x^{\frac{m}{n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Em%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D)
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
![\sqrt[3]{7}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%7D)
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Pretty sure it's A. (X times .5 equals Y)
Do you know what the answer choices are?
You probably are interested in expressing the given equation as a quadratic equation in u, as it will make it easy to find the solutions.
Let u = x²
So,
u² = x⁴
So, the given equation can be written as:
u² - 17u + 16 = 0
Now the equation is quadratic in u and the solutions can be calculated using quadratic formula or factorization.
