Complete question:
A casting with a mass of 500 kg rests on a surface with a slope of 20° to the horizontal. The coefficient of friction is 0.25.
Calculate;
(a) the component of the weight of the object perpendicular to the surface
(b) the component of the weight of the object parallel to the surface
Answer:
(a) the component of the weight of the object perpendicular to the surface is 4,604.5 N
(b) the component of the weight of the object parallel to the surface is 1,675.9 N
Explanation:
Given;
mass of the casting, m = 500 kg
angle of inclination of the casting, θ = 20⁰
the coefficient of friction, k = 0.25
(a) the component of the weight of the object perpendicular to the surface;
F⊥ = mgcosθ
F⊥ = 500 x 9.8 x cos20
F⊥ = 4,604.5 N
(b) the component of the weight of the object parallel to the surface
F|| = mgsinθ
F|| = 500 x 9.8 x sin(20)
F|| = 1,675.9 N
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That would be the Supreme Court!!!
Hope this helps!
MidnightQueen
