If u hade 1400 cookies and u separated them in 14difrent groups how many cookies would be in each group??
2 answers:
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Answer:
(1)
type-A:
type-B:
(2)
Step-by-step explanation:
We are given
type-A:
type-B:
(1)
At initial means t=0
For type-A:
we can plug t=0
For type-B:
we can plug t=0
(2)
we can set f(t)=g(t)
and then we can solve for t
we can draw graph of f(t) and g(t)
and then we can find intersection point
so, we got
Answer:
1). 0.903547
2). 0.275617
Step-by-step explanation:
It is given :
K people in a party with the following :
i). k = 5 with the probability of
ii). k = 10 with the probability of
iii). k = 10 with the probability
So the probability of at least two person out of the 'n' born people in same month is = 1 - P (none of the n born in the same month)
= 1 - P (choosing the n different months out of 365 days) =
1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)
=
=
= 0.903547
2).P( k = 10|at least 2 share their birthday in same month)
=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)
=
= 0.0.275617