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Bogdan [553]
2 years ago
12

I NEED THE ANSWR ASAP: Write the number as a power with a base of 5. 125^3

Mathematics
1 answer:
EastWind [94]2 years ago
5 0

Answer:

5^9

Step-by-step explanation:

I had this question before.

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Diego had $21.32 and gave $9.50 to Elena. How much did he have left?
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11.82

Step-by-step explanation: I know this because 21.32-9.50= 11.82

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A=1/2•e•m <br> solve the following formula for e
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Asim is going to cover the path with paving
leonid [27]

Answer: £210

Step-by-step explanation:

you do the cm they given you so if it’s 630cm x 120cm = 75,600

30cm x 30cm = 900cm

75,600 divided by 900 = 84

£2.50 x 84 = £210

5 0
3 years ago
Please pleaseeeee help me outtt, I need it quickkk will give brainliest
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Complete parts ​(a) through ​(c) below. ​(a) Determine the critical​ value(s) for a​ right-tailed test of a population mean at t
olga_2 [115]

Answer:

a) The critical value on this case would be t_{crit}=1.325

b) The critical value on this case would be t_{crit}=-1.345

c) The critical values on this case would be t_{crit}=\pm 2.201

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: \mu \leq \mu_0

Alternative hypothesis: \mu > \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

P(t_{20}>a) = 0.1

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be t_{crit}=1.325

Part b

The system of hypothesis on this case would be:

Null hypothesis: \mu \geq \mu_0

Alternative hypothesis: \mu < \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since its an lower tailed test we need to find b value a such that:

P(t_{14}

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be t_{crit}=-1.345

Part c

The system of hypothesis on this case would be:

Null hypothesis: \mu = \mu_0

Alternative hypothesis: \mu \neq \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=12-1=11

Since its a two tailed test we need to find c value a such that:

P(t_{11}>c) = 0.025 or P(t_{11}

And we can use excel in order to find this value with this function: "=T.INV(0.025,11)". The 0.025 is because we have 0.025 of the area on each tail.

The critical values on this case would be t_{crit}=\pm 2.201

5 0
3 years ago
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