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Wewaii [24]
4 years ago
6

There are 72 girls and 60 boys waiting to see A play in the school auditorium. They are seated in rows in the auditorium with th

e same number of students in each row. Each row has only girls or only boys. How many rows of girls will there be? How many rows of boys will there be?
Mathematics
2 answers:
borishaifa [10]4 years ago
5 0
To answer this problem you first find the GCF (Greatest common factor) between 60 and 72, which is 12. Next, to find how many rows of girls there are you divide 72 by 12. You get 6. There are 6 rows of girls. Next, you divide the number of boys which is 60 by twelve to find how many rows of boys there are and you get 5. there are 5 rows of boys.
zalisa [80]4 years ago
5 0
If each row had 12 students in it you would divide both 72 and 60 by 12 
72/12=6 rows of girls
And 60/12=5 rows of boys
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Ella has 0.5 lb of sugar. how much water should she add to make the following concentrations? Tell Ella how much syrup she will
makkiz [27]

Answer:

For 50% syrup, add 0.5 lb of water for 1 lb of syrup; for 5% syrup, add 9.5 lb of water for 10 lb of syrup; for 75% syrup, add 0.17 lb of water for 0.67 lb of syrup; for 1.5% syrup, add 32.8 lb of water for 33.3 lb of syrup.

Step-by-step explanation:

Let x represent the amount of water added.  This means the total mass of the syrup is represented by 0.5+x.

To find percentages, we divide the part by the whole.  For a 50% syrup, we need the part (sugar) compared to the whole (sugar + water) to equal 50%, or 0.50:

Multiply both sides by 0.5+x:

Using the distributive property, we have

0.5 = 0.5(0.5)+0.5(x)

0.5 = 0.25+0.5x

Subtract 0.25 from each side:

0.5-0.25 = 0.25+0.5x-0.25

0.25 = 0.5x

Divide both sides by 0.5:

0.25/0.5 = 0.5x/0.5

x = 0.5

For 50% syrup, add 0.5 lb of water.  This makes the total mass 0.5+0.5 = 1 lb.

For 5% syrup, we change the equation to equal 0.05 (5% = 5/100 = 0.05) and leave everything else the same:

Multiply both sides by 0.5+x:

Using the distributive property,

0.5 = 0.05(0.5)+0.05(x)

0.5 = 0.025 + 0.05x

Subtract 0.025 from both sides:

0.5-0.025 = 0.025+0.05x-0.025

0.475 = 0.05x

Divide both sides by 0.05:

0.475/0.05 = 0.05x/0.05

x = 9.5

For 5% syrup, add 9.5 lb of water; the total mass will be 9.5+0.5 = 10 lb.

For 75% syrup, set the equation equal to 0.75:

Using the distributive property,

0.5 = 0.75(0.5)+0.75(x)

0.5 = 0.375 + 0.75x

Subtract 0.375 from each side:

0.5 - 0.375 = 0.375 + 0.75x - 0.375

0.125 = 0.75x

Divide both sides by 0.75:

0.125/0.75 = 0.75x/0.75

0.17 = x

For 75% syrup, add 0.17 lb of water; the total mass is 0.17+0.5 = 0.67 lb.

For 1.5% syrup, set the equation equal to 0.015:

Using the distributive property,

0.5 = 0.015(0.5) + 0.015(x)

0.5 = 0.0075 + 0.015x

Subtract 0.0075 from each side:

0.5-0.0075 = 0.0075 + 0.015x - 0.0075

0.4925 = 0.015x

Divide both sides by 0.015:

0.4925/0.015 = 0.015x/0.015

32.8 = x

For 1.5% syrup, use 32.8 lb of water; the total mass is 32.8+0.5 = 33.3 lb.

I hope this is right and have a good day

3 0
3 years ago
Read 2 more answers
If sin x=2/9,x, in quadrant i, then find(without findingx): sin(2x), cos(2x), tan(2x)
Sergio039 [100]
We have that
<span>sin x=2/9

we know that
sin</span>² x+cos² x=1---------> cos² x=1-sin² x-----> cos² x=1-(2/9)²
cos² x=1-(4/81)------> (81-4)/81-----> 77/81
cos x=√(77/81)

Sin 2x = 2 sin x cos x-------> 2*(2/9)*(√(77/81))----> (4/81)*√77---> 0.43

Sin 2x=0.43
so
cos² 2x=1-sin² 2x---------> 1-[0.43]²-----> 1-[0.1878]----> 0.81
cos² 2x=0.81-----------> cos 2x=0.9

tan 2x=sin 2x/cos 2x--------> tan 2x=0.43/0.9---------> tan 2x=0.48

the answers are
sin 2x=0.43
cos 2x=0.9
tan 2x=0.48


8 0
4 years ago
Can someone help me with this?
Arisa [49]

Answer:

look at the picture

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
8-4(2+5²)÷12<br>answer? ​
mestny [16]

Answer:

-1 i think

Step-by-step explanation:

5 0
3 years ago
Factor completely.<br> - 3x² + 14x- 8
brilliants [131]

Answer =

= - 3x² + 14x - 8

= - 3x² + 12x + 2x - 8

= - 3x(x - 4) + 2(x - 4)

= (x - 4)(-3x + 2)

7 0
3 years ago
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