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scoundrel [369]
3 years ago
8

If sin x=2/9,x, in quadrant i, then find(without findingx): sin(2x), cos(2x), tan(2x)

Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0
We have that
<span>sin x=2/9

we know that
sin</span>² x+cos² x=1---------> cos² x=1-sin² x-----> cos² x=1-(2/9)²
cos² x=1-(4/81)------> (81-4)/81-----> 77/81
cos x=√(77/81)

Sin 2x = 2 sin x cos x-------> 2*(2/9)*(√(77/81))----> (4/81)*√77---> 0.43

Sin 2x=0.43
so
cos² 2x=1-sin² 2x---------> 1-[0.43]²-----> 1-[0.1878]----> 0.81
cos² 2x=0.81-----------> cos 2x=0.9

tan 2x=sin 2x/cos 2x--------> tan 2x=0.43/0.9---------> tan 2x=0.48

the answers are
sin 2x=0.43
cos 2x=0.9
tan 2x=0.48


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5 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

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230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
3 years ago
what is the product of 9.8 x 10 to the power of 3 and 8.8 x 10 to the power of 6 expressed in scientific notation
sergij07 [2.7K]

Answer:

9.8*10^3

= 9,800

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