Answer:
a). -65
b). -61
c). -20ab + 3bc +3ac
Step-by-step explanation:
According To the Question,
a). the sum of 72 − 104 + 5 and -32 + 4 - 10 .
- (72 − 104 + 5) + (-32 + 4 - 10)
- (-27) + (-38)
- -27 - 38
- -65
b). What should be added to 32 + 32 + 3 to get 3 + 3 , Let X be Added .
- Thus, (32 + 32 + 3) + X = 3 + 3
- 67 + X = 6
- X = 6 - 67
- X = -61
c). Subtract the sum of 12ab –10bc –18ac and 9ab + 12bc + 14ac from the sum of ab + 2bc and 3bc – ac.
- Thus, [(ab + 2bc) + (3bc – ac)] - [( 12ab –10bc –18ac) + (9ab + 12bc + 14ac)]
- (ab + 5bc - ac) - (21ab + 2bc - 4ac)
- ab + 5bc - ac - 21ab - 2bc + 4ac
- -20ab + 3bc + 3ac
5+5=10, 5+6=11, 5+7=12,etc.
