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REY [17]
3 years ago
9

12 − 7 = 2(3 + 5) + 6 − 17

Mathematics
1 answer:
larisa [96]3 years ago
5 0

It equals 5- hope this helps---

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What is the value of x and the length of segment DE?
Mandarinka [93]

Answer:

Part 1) x=6.6\ units

Part 2) DE=16.2\ units

Step-by-step explanation:

Part 1) Find the value of x

we know that

Triangles CDF and FDE are similar

therefore

The ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

CD/FD=FD/DE

\frac{5}{9}=\frac{9}{2x+3} \\ \\5*(2x+3)=9*9\\ \\10x+15=81\\ \\10x= 81-15\\ \\10x=66\\ \\ x=6.6\ units

Part 2) Find the length of DE

DE=2x+3

substitute the value of x

DE=2(6.6)+3=16.2\ units

8 0
3 years ago
Read 2 more answers
The four rectangles shown have different side lengths.
RUDIKE [14]
Answer is <span>D.
A and D

A = 2(6+2) = 16
D = 2(4+3) = 16
both have perimeters = 16</span>
8 0
3 years ago
Write the following equation in slope-intercept form.<br> 1/3 - y+6=0
Radda [10]

Answer:

y=19/3

Step-by-step explanation:

4 0
3 years ago
then difference between the cubes of two numbers is twice the value of the perfect square of a possitive Intiger
PSYCHO15rus [73]
There are many solutions. But what do you mean with a perfect square of a number. I thought a number IS a perfect square or not.

For example, the difference between 2² and 4² = 12, which is twice the number 6, which is √36

The difference between 2² and 6² = 32, which is twice the number 16, which is a perfect square.

So choose depending on your interpretation of the question... ;-)
8 0
3 years ago
Find the equation of the plane that is parallel to the vectors left angle 3 comma 0 comma 3 right angle and left angle 0 comma 1
Sholpan [36]

Answer:

x + 3y -z - 3 = 0      

Step-by-step explanation:

We have to find the equation of plane that is parallel to the vectors

\langle 3,0,3\rangle, \langle0,1,3\rangle

The plane also passes through the point (2,0,-1).

Hence, the equation of plane s given by:

\displaystyle\left[\begin{array}{ccc}x-2&y-0&z+1\\3&0&3\\0&1&3\end{array}\right]\\\\=(x-2)(0-3) - (y-0)(9-0) + (z+1)(3-0)\\=-3(x-2)-9y+3(z+1)\\\Rightarrow -3x + 6 - 9y + 3z + 3 = 0\\\Rightarrow 3x + 9y -3z -9 = 0\\\Rightarrow x + 3y -z - 3 = 0

It is the required equation of plane.

4 0
3 years ago
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