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3 years ago

12 − 7 = 2(3 + 5) + 6 − 17

Mathematics

1 answer:

larisa [96]3 years ago

5 0

It equals 5- hope this helps---

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9. How many gallons of paint will you need to buy if you are painting a room that is 30 ft by

pentagon [3]

Answer:

To paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon

Step-by-step explanation:

Given as :

The Length of wall = L = 50 ft

The width of wall = W = 30 ft

The height of wall = H = 50 ft

Each gallon of paints should cover 300 sq feet

Let the amount o gallon required to paint the room = x

SO, Area of four wall = 2 × ( L + W ) × H

Or, Area of four wall = 2 × ( 50 + 30 ) × 50

Or, Area of four wall = 2 × ( 80 ) × 50

SO, Area of four wall = 8000 ft²

∵ To paint 300 sq ft the amount of paint required = 1 gallon

∴ To paint 8000 sq ft the amount of paint required = 26.67 gallon

Hence ,to paint the room with dimension 30 ft by 50 ft by 50 ft is 26.67 gallon answer

6 0

3 years ago

G<br> H<br> 2.5(JK)<br> 12<br> к<br> L<br> F<br> What is HL?

Alchen [17]

<h3>Answer: 21</h3>

=================================================================

Work Shown:

The diagram shows that JK = 12 and GF = 2.5*(JK) = 2.5*12 = 30

The midsegment HL will be the average of the two lengths it is parallel to.

We'll add up the values and then cut the result in half

HL = (JK+GF)/2

HL = (12+30)/2

HL = 42/2

HL = 21

3 0

3 years ago

Which represents the number 16,807 in exponential form

Naya [18.7K]

7^5. Found by trial and error.

3 0

3 years ago

Please help me with this and find x!! Thank you, only if you know!

scoray [572]

Answer:

x = 9.8

Step-by-step explanation:

to find x, use pythagorean theorem

$a^{2} = c^{2} - b^{2}$

$a^{2} = 14^{2} - 10^{2}$

$a^{2} = 196 - 100$

$a^{2} = 96$

$\sqrt{a^2} = \sqrt{96}$

$a = 9.7979$ ⇒ 9.8

7 0

3 years ago

Read 2 more answers

Find the measure of arc DB in P<br><br>please hurry if you can

jeyben [28]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree$

[ linear pair ]

$\qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree$

$\qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

8 0

2 years ago