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Shtirlitz [24]
2 years ago
14

The graph shows the number of paintballs a machine launches, y, in x seconds:

Mathematics
1 answer:
aalyn [17]2 years ago
5 0
The answer is B, 20 balls in 4 seconds. Or 5 balls per second.
You might be interested in
Is 11/13 a ratio in simplest form
Molodets [167]
Yes 11/13 cannot be simplified anymore
5 0
3 years ago
Graham graphs the following system of equations to determine its solution.
V125BC [204]

Answer: (2,2)

Step-by-step explanation:

I'm going to use substitution to solve this:

First, I use the second equation to solve for y in terms of x.

2x - y = 2

-y = 2 - 2x

y = 2x - 2

Then, I plug the value for y into the first equation:

2x + 4y = 12

2x + 4(2x - 2) = 12

2x + 8x - 8 = 12

10x - 8 = 12

10x = 20

x = 2

Now that we have x, we can plug it into either equation (I used the first) to get the value for y:

2x + 4y = 12

2(2) + 4y = 12

4 + 4y = 12

4y = 8

y = 2

We get the point (2,2) as a solution.

Note: This is the point where both lines intersect.

3 0
2 years ago
Which of the following statement is not a reason for sampling?
VladimirAG [237]

Answer:

Studying every single instance of a thing is impractical or too expensive

Step-by-step explanation:

With sampling we a have a lot of data without much effort.

3 0
2 years ago
Suppose that F is an inverse square force field below, where c is a constant.
Andre45 [30]

Answer:

Forces in our Universe

Step-by-step explanation:

a)

First of all we have,

F(r) = \frac{cr}{|r|^{3} }

and,

r = xi+yj+zk

We need to define a function that allows us to find said change based on r, so one of the functions that shows that change is,

f(r) = - c /|r|

That is,

\nabla f = F

For this case F is a conservative field and the line integral is independent of the path. Thus, defining  P_{1} = (x_{1}, y_{1}, z_{1}) and P_{2} = (x_{2}, y_{2}, z_{2}) . So the amount of work on the movement of the object from P1 to P2 is,

W=\int\limits_c  {F} \, dr

W= f(P_{1}-P_{2})

W= \frac{c}{(x_{2}^2+ y_{2}^2+ z_{2}^2)^{1/2} } -\frac{c}{(x_{1}^2+ y_{1}^2+ z_{1}^2)^{1/2}}

W= c(\frac{1}{d1}-\frac{1}{d2}  )

2) The gravitational force field is given by,

F(r) =-\frac{mMGr}{ |r|^3}

The maximum distance from the earth to the sun is 1.52*10 ^ 8 km and the minimum distance is 1.47*10 ^ 8km. The mass values of the bodies are given by m = 5.97*10 ^ {24}kg, M = 1.99 *19 ^ {30}kg and the constant G is 6.67 * 10 ^{ -11 } \frac{Nm ^ 2}{kg^2}

In this way we raise the problem like this,

c= -mMG

W= -mMG (\frac{1}{1.52*10 ^ 8} -\frac{1}{1.47*10 ^ 8} )

W= -(5.95*10^{24})(1.99*10^{30})(6.67*10^{-11})(-2.2377*10^{-10})

W \approx 1.77*10^{35}}J

5 0
2 years ago
Please help. !!!!!!!!
Kryger [21]
Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So 
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)
8 0
2 years ago
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