Answer:
(-1, -7)
Step-by-step explanation:
Used desmos, also, in these situations I believe you can take the number inside the brackets and make it negative and keep the number outside the same to find the vertex.
Multiply the 37 and 23 for 851 plus the triangles must be above it so its 1035 in squared
Answer:
2.15
Step-by-step explanation:
Answer:A,C,E
Step-by-step explanation:
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
