All categories

3 years ago

Which of the named angles is not an angle found in the picture?

Mathematics

2 answers:

katen-ka-za [31]3 years ago

6 0

The angle not found in the picture is C. The answer is C.

Andreas93 [3]3 years ago

4 0

Answer:c

Step-by-step explanation:

cccccccccc

You might be interested in

Help me please!!! :((

snow_tiger [21]

Answer:

mark brainliest im grinding ranks

Step-by-step explanation:

4 0

3 years ago

I have homework that says

Talja [164]

Let x = number of cans
let c = cost
c = .70x

6 0

3 years ago

In pentagon $MATHS$, $\angle M \cong \angle T \cong \angle H$ and $\angle A$ is supplementary to $\angle S$. How many degrees ar

gavmur [86]

Answer:

H = 120°

Step-by-step explanation:

The sum of the internal angles of a polygon with n sides is given by the formula:

S = (n-2)*180

So, for a pentagon, we have n = 5, then:

S = (5-2)*180 = 540°

So we have that:

M + A + T + H + S = 540° (eq1)

M = T = H (eq2)

A + S = 180° (eq3)

Using the second and third equation in the first one, we have:

H + H + H + 180 = 540

3H = 360

H = 120°

3 0

4 years ago

Please help me out wit this question

Ber [7]

Answer:

Area of the circular sidewalk = 405 m²

Step-by-step explanation:

Radius of the circular flower bed = 20 m

Area of the circular bed = πr²

Here r = radius of the circle

Area of the circular bed = π(20)²

= 400π square meter

Radius of the larger circle = Radius of the flower bed + width of the sidewalk

= 20 + 3

= 23 m

Area of the larger circle = π(23)²

= 529π m²

Area of the circular sidewalk = Area of the larger circle - Area of the flower bed

= 529π - 400π

= 129π

= 129(3.14)

= 405.06 square meters

≈ 405 square meters

6 0

3 years ago

Write various of the equation of a line that passes through (-6, 3) and has a slope of - 1/3

pishuonlain [190]

Answer:

$\large\boxed{y-3=-\dfrac{1}{3}(x+6)-\text{point-slope form}}\\\boxed{y=-\dfrac{1}{3}x+1-\text{slope-intercept form}}\\\boxed{x+3y=3-\text{standard form}}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

We have

$m=-\dfrac{1}{3},\ (-6,\ 3)\to x_1=-6,\ y_1=3$

Substitute:

$y-3=-\dfrac{1}{3}(x-(-6))\\\\y-3=-\dfrac{1}{3}(x+6)$

Convert to the slope-intercept form

$y=mx+b$

$y-3=-\dfrac{1}{3}(x+6)$ use the distributive property

$y-3=-\dfrac{1}{3}x-2$ add 3 to both sides

$y=-\dfrac{1}{3}x+1$

Convert to the standard form

$Ax+By=C$

$y=-\dfrac{1}{3}x+1$ multiply both sides by 3

$3y=-x+3$ add x to both sides

$x+3y=3$

5 0

3 years ago

Which of the named angles is not an angle found in the picture?​

Which of the named angles is not an angle found in the picture?