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mel-nik [20]
4 years ago
12

the rectangle below has an area of 72 units give the area of the scale copy of the rectangle with a scale factor of 1/3 show wor

k
Mathematics
1 answer:
Anestetic [448]4 years ago
4 0
The answer would be 24 because 72 divided by 3 (1/3 scale factor
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Please explain how to do #6 i know the work is right but i don’t understand it
mariarad [96]
Since this is part of a packet, there's a lot of prior knowledge you need to understand the question.
1) The angle of elevation is the angle between the horizontal and the light of sight from the object to the observer (see picture 1).

2) A lot of the units are from work done by an Indian astronomer. The line of sight (light blue in picture 1) is r = 3438 (I think you might have forgotten to finish writing the number). r, or 3438, is the distance from the earth to the sun used by Indian Astronomers. 

3) The table shows units in jya(θ<span>°). Jya is a Sanskrit (ancient Indian language) word. It stands for the length of half of a chord that connects two endpoints of a circle (kinda confusing and more information than you need to know - but it's the green line in picture 2).
What's important is: </span>jya(θ°) = r*sin(θ°)



Now let's tackle the problem:
1) You know that the angle of elevation is 67.5°. Using the chart, the only important value is the second from the bottom. jya(67.5°) = 3177. 

2) Remember that jya(θ°) = r*sin(θ°). 
Also remember that sine of an angle is \frac{opposite}{hypotenuse}. In this problem, r, the distance from the earth to the sun, happens to be the hypotenuse of the triangle since its the longest edge. 

3) Notice that you're dividing jya(θ°) (aka r*sin(θ°)) by r = 3438. That will give you sin(θ°) by itself. Then you're multiplying that sin(θ°) by 1 AU, which we are told is the actual distance of the hypotenuse/distance from earth to sun. Since sine = \frac{opposite}{hypotenuse} that gives you the apparent length of the opposite side = apparent height of the sun.

The math is a bit weird, but you're basically multiplying sine by the apparent distance 1AU to get the apparent height, instead of multiplying sine by the estimated height r = 3438. Dividing 3177 by 3438 gives you sin(67.5°). Then multiplying sin(67.5°) by the apparent hypotenuse, 1AU, gives you the apparent height. That's how I'm understanding it!

6 0
3 years ago
Hector spent 3/4 of his money the day after he cashed his paycheck of $50. Let m represent the amount of money Hector spent.
Allisa [31]
The answer is 37.5
hector spend $37.5 
4 0
4 years ago
Read 2 more answers
What is the slope of the line that passes through the points (-4, -9) and (5, 3)
egoroff_w [7]

Answer:

4/3

Step-by-step explanation:

Moving from (-4, -9) to (5, 3), x (the 'run') increases by 9 from -4 to 5, and y (the 'rise') increases by 12 from -9 to +3.  Thus, the slope of the line connecting the two points is

m = rise / run = 12/9 = 4/3

It may help to think of the change in x (9) as the horizontal leg of a right triangle and the change in y (12) as the vertical leg.  Then  

m = (vertical leg length) / (horizontal leg length) = 12/9 = 4/3

5 0
3 years ago
15 POINTS (Will MARK BRAINLIEST) Simply theses problems
stiks02 [169]

Answer:

Part A: 108

Part B: 125

Part C: 1.71 x 10^-4

Part D: 0.2

Part E: 0.040

Sorry for the wait, laptop is being slow :/

I hope this helps.

4 0
3 years ago
PLEASE HELP ME WITH THIS ONE
otez555 [7]

the answer is B. 2

Both are close to 2 but a little under or a little over

3 0
3 years ago
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