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andrew11 [14]
3 years ago
14

An ice chest contains 7 cans of apple juice, 8 cans of grape juice, 5 cans of orange juice, and 6 cans of mango juice. Suppose t

hat you reach into the container and
randomly select three cans in succession. Find the probability of selecting three cans of orange juice.
Mathematics
1 answer:
Veronika [31]3 years ago
4 0

Answer:

P(0)=100%

P(x)=0 when x ≠ 0

Step-by-step explanation:

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A=1/2 bh (base/height)<br> =.5(12)4<br> a=24ft<br> how did i get the answer a=24?
vampirchik [111]
That’s what i got
step by step explanation
4 0
3 years ago
Point M is the midpoint of AB. The coordinates of point A are (−7, 1) and the coordinates of M are (−2, 2). What are the coordin
notka56 [123]

Answer:

\huge{\boxed{\sf{ ( 3 , 3 ) }}}

Step-by-step explanation:

Co-ordinates of point A = ( -7 , 1 )

Co-ordinates of point M = ( -2 , 2 )

Let the co-ordinates of point B be ( x , y )

A ( -7 , 1 ) \longrightarrow ( x1 , y1 )

B ( x , y ) \longrightarrow ( x2 , y2 )

Now,

Midpoint = (\frac{x1 + x2}{2}  , \frac{y1 + y2}{2} )

⇒( -2 , 2 ) = ( \frac{-7 + x}{2}  , \frac{1 + y}{2} )

Finding the value of x :                    

⇒-2 = \frac{-7 + x}{2}

Do cross multiplication                

⇒-4 = -7 + x

⇒-7 + x = -4

⇒x = -4 + 7

⇒x = 3

Now, finding the value of y

⇒2 = \frac{1+y}{2}

Do cross multiplication

⇒4 = 1+y

⇒1+y = 4

⇒y = 4 - 1

⇒y = 3

Hence, The co-ordinates of point B = ( 3 , 3 )

Hope I helped!

Best regards!

~\text{ TheAnimeGirl}

4 0
3 years ago
Two sections of a class took the same quiz. Section A had 15 students who had a mean score of 80, and Section B had 20 students
Nezavi [6.7K]

Answer: A. 85.7

Step-by-step explanation:

Given : Two sections of a class took the same quiz.

Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.

We know that  , \text{Mean}=\dfrac{\text{Sum of observations}}{\text{No. of observations}}

Then , for section A :

\text{Mean score }=\dfrac{\text{Sum of scores in sec A}}{\text{No. of students}}

\Rightarrow\ 80=\dfrac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80\times15=1200

Similarly in Section B, \text{Sum of scores in sec B}=90\times20=1800

Total scores = Sum of scores in sec A+Sum of scores in sec B

=1200+1800=3000

Total students = Students in sec A +Students in sec B

=15+20=35

Now , the mean score for all of the students on the quiz =\dfrac{\text{Total score}}{\text{Total students}}

=\dfrac{3000}{35}=85.7142857143\approx85.7

Hence, the approximate mean score for all of the students on the quiz = 85.7

Thus , the correct answer is option A. 85.7.

7 0
3 years ago
What is the lowest value in the set of data represented by the following box-and-whisker plot?
Sever21 [200]
D.11.5 because when you bring the line and the dot it is 11.5
8 0
3 years ago
Read 2 more answers
The stock of Company A lost 2% today to $46.55. What was the opening price of the stock in the beginning of the day?
cluponka [151]

Answer:

$2327.5

Step-by-step explanation:

The stock of company A lost 2% today .

Let the price of the stock at the beginning of the day be A.

Therefore, a 2% loss of A = $46.55

That’s

2% /100% x A = $46.55

0.02 x A = $46.55

Divide both sides by 0.02

0.02/0.02 x A = $46.55/0.02

A = $2327.5

The price of stock at the beginning of the opening day was $2327.5

4 0
3 years ago
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