All categories

3 years ago

[15 POINTS] FIND THE LENGTH OF SIDE AB IN THE TRIANGLE SHOWN

Mathematics

1 answer:

cupoosta [38]3 years ago

7 0

Using Pythagoras theorem, we have
AC^2=AB^2+BC^2
(9)^2=AB^2+(7)^2
81=AB^2+49
81-49=AB^2
32=AB^2
√32=AB

You might be interested in

I will FREIND AND 10PTS

Step2247 [10]

The answer is 6x + 0.50x= 2.50

6 0

3 years ago

Find the least common multiple.

vovangra [49]

Answer:

C - 3,600

Step-by-step explanation:

100 16 45 ÷ 2

50. 8. 45 ÷ 2

25. 4. 45 ÷ 2

25. 2. 45. ÷ 2

25. 1. 45. ÷ 3

25. 1. 15. ÷ 3

25. 1. 5. ÷ 5

5. 1. 1. ÷ 5

1. 1. 1

L.C.M = 2 x 2 x 2 x 2 x 3 x 3 x 5 x 5 = 3, 600

I know this may be confusing but if you don't understand, you're welcome to ask.

7 0

4 years ago

Hello, I need assistance with the attached problem. My answer was incorrect

Semmy [17]

Answer:

(a) 480 + 1640

Step-by-step explanation:

I don't really know what (b) is

but hope this helped

6 0

3 years ago

An item costs $440 before tax, and the sales tax is $13.20.

Ahat [919]

Answer:

Step-by-step explanation:

13.2 / 440 = 0.03

0.3*100 = 3%

3 0

2 years ago

A survey is to be conducted to determine the average driving in miles by Minnesota State University, Mankato students. The inves

Nadusha1986 [10]

Answer:

$n=(\frac{1.75(8.2)}{1.5})^2 =91.52 \approx 92$

So the answer for this case would be n=92 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =1.5 and we are interested in order to find the value of n, if we solve n from equation (b) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 92% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.04;0;1)", and we got $z_{\alpha/2}=1.75$ , replacing into formula (b) we got:

$n=(\frac{1.75(8.2)}{1.5})^2 =91.52 \approx 92$

So the answer for this case would be n=92 rounded up to the nearest integer

5 0

3 years ago