Answer:
2y² + 9
---------------
15y³
Step-by-step explanation:
Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.
Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.
Focus now on the first fraction: 2 / (15y). Multiplying numerator and denominator of this fraction by y² results in
y²·2 2y²
--------- → ----------
y²·15y 15y³ ←This is the correct LCD
Multiplying numerator and denominator of the second fraction by 3 results in:
3·3 9
------------ → ---------
3·5y³ 15y³ ←This is the correct LCD
So now those two original terms look like:
2y² 9
--------- + --------
15y³ 15y³
and this can be written in simpler form as:
2y² + 9
---------------
15y³
Answer:
yea i can help
Step-by-step explanation:
Answer:
<u>The answer is -4 3/5</u>
Step-by-step explanation:
Let's reduce to its simplest form:
-3/5 + (-8/2) =
Step 1: Lowest Common Denominator (10):
- 6/10 + (-40/10) =
Step 2: Solve the parentheses:
- 6/10 - 40/10 =
Step 3: Subtract the fractions:
-46/10
Step 4: Simplify (Dividing by 2):
-23/5
Step 5: Converting the fraction to mixed number:
-4 3/5
<u>The answer is -4 3/5</u>
Hello there,
The word "product" mean's to multiply.
So we are going to do 5 x 10.
This will give us 50 because when we do
10+10+10+10+10 is give's us 50. That is
what multiplication mean's.
Hope this helps
Your correct answer will be 50 card's
~Jurgen
Answer:
The Length of <em>JK</em> is 10
Step-by-step explanation:
Because <<em>J </em>is congruent to <<em>L</em> we know that the triangle in question must be isosceles as in an isosceles triangle two angles opposite of each other are equal. (This is also true for equilateral triangles, however, in an equilateral triangle all sides must be congruent, so we can rule equilateral out as <em>LJ </em>is not congruent to <em>KL.) </em>This means that the triangle must be isosceles.
In an isosceles triangle the side opposite each other are congruent, and the angles opposite each other are congruent when split down the line of symmetry.
Therefor, the length of <em>JK </em>must be congruent to the length of <em>KL. </em>In other words if <em>JK </em>= 10, then <em>KL </em>must equal 10 as well.
